<em>You have not provided the coordinates for the original object i.e. the square PQRS, therefore, I am taking the sample vertices of the square PQRS to provide an exact answer, which anyways would help you in terms of clearing your concept.</em>
The sample coordinates of the square PQRS are: P(1, -1), Q(1, 2), R(-2, 2). and S(-2, -1)
Answer:
When the square PQRS withe vertices P(1, -1), Q(1, 2), R(-2, 2). and S(-2, -1) is rotated 90° clockwise using the origin as the center of rotation, the vertices of the image P’Q’R’S’ will be:
Step-by-step explanation:
<em><u>The rule for an object rotated 90° clockwise using the origin as the center of rotation</u></em>
"When the point , let say A (x, y) is rotated through
clockwise about the origin, the point A (x, y) takes the image A' (y, -x)."
For example, let suppose there is a square PQRS with the vertices as:
As we know that When the point , let say A (x, y) is rotated through
clockwise about the origin, the point A (x, y) takes the image A' (y, -x).
So,
When the square PQRS is rotated 90° clockwise using the origin as the center of rotation, the vertices of the image P’Q’R’S’ will be: