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kiruha [24]
4 years ago
10

How are positive ions different from neutral atoms

Physics
1 answer:
Elena L [17]4 years ago
8 0
Positive ions have lost one or more electrons so have a positive charge rather than a neutral one.
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Analyze the given velocity time graph
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Where' the graph

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What does the Bohr Model show us?
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2

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Roads often have to be repaved because they crack over time. Sometimes this cracking is due to the fact that the roads (as well
Finger [1]
B. Physical Change - T<span>he molecules do not change shape or size. They do not contract or expand only.</span>
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3 years ago
Two resistors with values of 6.0 W and 12 W are connected in parallel. This combination is connected in series with a 2.0 W resi
Murljashka [212]
Well, first of all, you really shouldn't use ' W ' for the unit when you
talk about resistors.

You may have seen the resistors written as 6ω, 12ω, and 2ω in your
book or on the homework sheet. But that little symbol ' ω ' is not a ' w '.
It's the small Greek letter 'omega'. The CAPITAL omega is ' Ω '. It's used
to label resistors because it's short for "ohms". So the resistors in this
problem have resistances of 6Ω, 12Ω, and 2Ω, and we have to do some
manipulating of the individual resistors to find out what resistance the
battery actually sees.

The parallel combination of the first two resistors looks like a single
resistor, whose value is

1 / (1/6 + 1/12)

= 1 / (2/12 + 1/12)

= 1 / (3/12)

= 12/3 = 4Ω .

Now, that parallel combination is connected in series with 2Ω .
All three resistors together look like a single resistor of

4Ω + 2Ω = 6Ω .

So the battery thinks there's a single resistor connected to it,
with 6Ω of resistance. The current out of the battery is

I = V / R = (24v) / (6Ω) = 4 Amperes.

That 4 Amperes of current will split between the parallel resistors,
but it will ALL flow through the series 2Ω resistor because there's
no other path through that part of the circuit.

So the current through the 2Ω resistor is 4 Amperes. (B).

Note:
The POWER dissipated by the 2Ω resistor is

P = I² R = (4A)² · (2Ω) = 32 watts .

This is a fair amount of heat, so you'll need to provide some way
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8 0
3 years ago
A ship sailing in the Gulf Stream is heading 25.0º west of north at a speed of 4.00 m/s relative to the water. Its velocity rela
ASHA 777 [7]

Answer:

Velocity of Gulf Stream= 34.5^\circ west of north at a speed of 2.03\ \rm m/s

Explanation:

Given

  • speed of ship relative to Gulf stream=25^\circ  west of north at a speed of 4 m/s
  • speed of ship relative to earth=5^\circ  west of north at a speed of 4 .8 m/s

Let V_S be the velocity of the ship relative to the earth and V_{sg} be the velocity of the ship with respect to the Gulf stream

Let the west direction be  negative x axis and north direction be positive x axis

Now

V_{sg}=-4\sin25^\circ \vec i+4\cos25^\circ \vec j\\V_s-V_g=-4\sin25^\circ \vec i+4\cos25^\circ \vec j\\-4.8\sin5^\circ \vec i+4.8\cos5^\circ \vec j-V_g=-4\sin25^\circ \vec i+4\cos25^\circ \vec j\\Vg=-1.68\vec\ i+1.156\vec\ j\ \rm m/s\\

magnitude of the velocity is given by

V_g=\sqrt{(1.68^2+1.156^2)}\\V_g=2.03\ \rm m/s\\

Let the velocity of gulf stream makes an angle \theta with the positive y axis we have

\tan\theta=\dfrac{1.156}{1.68}\\\theta=34.5^\circ

Velocity of Gulf Stream 34.5^\circ west of north at a speed of 2.03\ \rm m/s

8 0
3 years ago
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