Just multiply them
s=vt = 20*15 = 300 m
Answer:
14 m/s^2
Explanation:
We have to use the equation F=ma because the question is a Newton's second law question.
First, list known values
F (force) = 70 N
m (mass) = 5 kg
a (acceleration) = ? (we have to solve for this)
Second, plug in known values into equation.
F=ma
70=5a
Third, solve. To solve this all you have to do is divide both sides by 5
70/5=5/5a
Fourth, your answer will be 14 meters per second squared (m/s^2)
I hope this answer helps and have a great day!
I believe it is B! Also I am just typing this stuff because it needs to be 20 characters long for some reason! Hope this helps!
Answer:
557.7Nm
Explanation:
We are given that
Radius,r=1.9 m
Angular speed,
Time,t=3.5 s
Initial angular velocity,
We have to find the large torque would have to be exerted .
Where
Substitute the values