What does the Bohr Model show us?

Rings of dust and icy particles are found around which planets? a. all planets which have moons associated with them b. only Sat

lisov135 [29]

Answer:

d. all four jovian planets.

Explanation:

The Jovian planets are as follows -

URANUS , SATURN , JUPITER, and NEPTUNE .

All these four jovian planets are having the rings , and the rings are made up of infinite number of small pieces of the ice and the rock .

Hence ,

These planets are comparatively small and dense cores surrounded by massive layers of gas .

5 0

3 years ago

Un cuerpo gira con movimiento circular uniforme un ángulo total de 1080° en 20

LekaFEV [45]

Velocidad angular = (angulo total) / (tiempo total)

Velocidad angular = (1080 grados) / (20 segundos)

Velocidad angular = (1080/20) g/s

Velocidad angular = 54 g/s

Pero 180 grados = π radianes

V.A. = (54 g/s) x (π rad / 180 g)

V.A. = (54π gr-rad / 180 seg-gr)

V.A. = 0.3π rad/seg

V.A. = aproximadamente 0.942 rad/seg

7 0

3 years ago

4. A driver travels 135 km, east in 1.5 h, stops for 45 minutes for lunch,

stira [4]

Answer:

The driver's average velocity is 82.35 km/h.

Explanation:

Given:

The motion of the driver can be divided into 3 parts:

i. Displacement of the driver in 1.5 hours = 135 km

ii. Rest for 45 minutes.

iii. Displacement in next 2 hours = 215 km

The direction of motion remains same (east).

Now, total displacement of the driver is, $D_{Total}=135+215=350$ km.

Rest time is 45 minutes. Converting it to hours, we need to use the conversion factor $1\textrm{ min} = \frac{1}{60}$ hour.

So, 45 minutes in hours is equal to $\frac{45}{60}=0.75$ hours.

Now, total time taken for the complete journey is, $\Delta t=1.5+\frac{45}{60}+2=1.5+0.75+2=4.25\textrm{ h}$

Average velocity is given as:

$v_{avg}=\frac{\textrm{Total displacement}}{Total time}=\frac{350}{4.25}=82.35\textrm{ km/h}$

Therefore, the driver's average velocity is 82.35 km/h

4 0

3 years ago

A sled of mass m is being pulled horizontally by a constant horizontal force of magnitude F. The coefficient of kinetic friction

rusak2 [61]

I'll bite:

-- Since the sled's mass is 'm', its weight is 'mg'.

-- Since the coefficient of kinetic friction is μk, the force acting opposite to the direction it's sliding is (μk) times (mg) .

-- If the pulling force is constant 'F', then the horizontal forces on the sled
are 'F' forward and (μk · mg) backwards.

-- The net force on the sled is (F - μk·mg).
(I regret the visual appearance that's beginning to emerge,
but let's forge onward.)

-- The sled's horizontal acceleration is (net force) / (mass) = (F - μk·mg) / m.
This could be simplified, but let's not just yet.

-- Starting from rest, the sled moves a distance 's' during time 't'.
We know that s = 1/2 a t² , and we know what 'a' is. So we can write

 s = (1/2 t²) (F - μk·mg) / m .

Now we have the distance, and the constant force.
The total work is (Force x distance), and the power is (Work / time).
Let's put it together and see how ugly it becomes. Maybe THEN
it can be simplified.

Work = (Force x distance) = F x (1/2 t²) (F - μk·mg) / m

Power = (Work / time) = F (t/2) (F - μk·mg) / m 

Unless I can come up with something a lot simpler, that's the answer.

To simplify and beautify, make the partial fractions out of the
2nd parentheses:
  F (t/2) (F/m - μk·m)

I think that's about as far as you can go. I tried some other presentations,
and didn't find anything that's much simpler.

Five points,ehhh ?

4 0

3 years ago

Read 2 more answers

If the voltage across the first capacitor (the one with capacitance

RoseWind [281]

The answer to this question is: it depends. It depends on the arrangement of the capacitors in a circuit: it can be either in series or in parallel. The difference is shown in the picture.

Capacitors are like batteries in a way that they store power from the source. It has some rules depending on the type of circuit. For parallel circuits, the voltage across each capacitor is equal. Therefore, V₁=V₂=V₃.

On the other hand, if the capacitors are arranged in series, the voltage across each capacitor should add up to the total voltage of the source. Therefore, V₁+V₂+V₃ = Total Voltage.

8 0

3 years ago