All categories

3 years ago

Find the volume please

Mathematics

1 answer:

makkiz [27]3 years ago

6 0

Answer:

586.4 in

Step-by-step explanation:

i) V1 = πr²h

= π x 4² x 9

= 452.4

ii) V2 = 2/3 x π x r³

= 2/3 x π x 4³

= 134

iii) V = V1 + V2

V = 452.4 + 134

= 586.4

You might be interested in

A 32 foot tall tree casts a shadow that is 48 feet long. How far away from the tree is a

sveticcg [70]

Answer:

39 feet

Step-by-step explanation:

take the tree as AB , the distance between the man and the tree as BC, the distance between the man and the tip of the shadow CD and the point intersecting the hypotenuse CE

since CE parallel to AB we can BPT

CE/AB = CD/BD

6/32= CD/48

CD = 9 feet

since CD is feet

BC is 48-9 = 39 feet

3 0

2 years ago

X = [?]<br> 5x - 5<br> 2x + 10

Ket [755]

Answer:

I thinks it’s 7x + 5

Step-by-step explanation:

7 0

3 years ago

Verify that the given point is on the curve and find the lines that are (a) tangent and (b) normal to the curve at the given poi

lara [203]

For each curve, plug in the given point $(x,y)$ and check if the equality holds. For example:

(I) (2, 3) does lie on $x^2+xy-y^2=1$ since 2^2 + 2*3 - 3^2 = 4 + 6 - 9 = 1.

For part (a), compute the derivative $\frac{\mathrm dy}{\mathrm dx}$ , and evaluate it for the given point $(x,y)$ . This is the slope of the tangent line at the point. For example:

(I) The derivative is

$x^2+xy-y^2=1\overset{\frac{\mathrm d}{\mathrm dx}}{\implies}2x+x\dfrac{\mathrm dy}{\mathrm dx}+y-2y\dfrac{\mathrm dy}{\mathrm dx}=0\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x+y}{2y-x}$

so the slope of the tangent at (2, 3) is

$\dfrac{\mathrm dy}{\mathrm dx}(2,3)=\dfrac74$

and its equation is then

$y-3=\dfrac74(x-2)\implies y=\dfrac74x-\dfrac12$

For part (b), recall that normal lines are perpendicular to tangent lines, so their slopes are negative reciprocals of the slopes of the tangents, $-\frac1{\frac{\mathrm dy}{\mathrm dx}}$ . For example: