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gulaghasi [49]
3 years ago
5

Find the volume please

Mathematics
1 answer:
makkiz [27]3 years ago
6 0

Answer:

586.4 in

Step-by-step explanation:

i) V1 = πr²h

       = π x 4² x 9

       = 452.4

ii) V2 = 2/3 x π x r³

         = 2/3 x π x 4³

         = 134

iii) V = V1 + V2

    V = 452.4 + 134

        = 586.4

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The graphs of g(x) = x³- ax² + 6 and h(x) = 2x² + bx + 3 touch when x = 1. Therefore, the tangent to
Olegator [25]

Answer:

(1,\, 10).

Step-by-step explanation:

Differentiate each function to find an expression for its gradient (slope of the tangent line) with respect to x. Make use of the power rule to find the following:

g^\prime(x) = 3\, x^2 - 2\, a\, x.

h^\prime(x) = 2\, (2\, x) + b = 4\, x  + b.

The question states that the graphs of g(x) and h(x) touch at x = 1, such that g^\prime(1) = h^\prime(1). Therefore:

3 - 2\, a = 4 + b.

On the other hand, since the graph of g(x) and h(x) coincide at x = 1, g(1) = h(1) (otherwise, the two graphs would not even touch at that point.) Therefore:

1 - a + 6 = 2 + b + 3.

Solve this system of two equations for a and b:

\begin{aligned}& a + b = 2 \\ & 2\, a + b = -1\end{aligned}.

Therefore, a = -3 whereas b = 5.

Substitute these two values back into the expression for g(x) and h(x):

g(x) = x^3 + 3\, x^2 + 6.

h(x) = 2\, x^2 + 5\, x + 3.

Evaluate either expression at x = 1 to find the y-coordinate of the intersection. For example, g(1) = 1 + 3 + 6 = 10. Similarly, h(1) = 2 + 5 + 3 = 10.

Therefore, the intersection of these two graphs would be at (1,\, 10).

6 0
3 years ago
Pls help with this ..its to be submitted this monday.....pls pls pls
Svet_ta [14]

Answer:

9pr = 2q^2

Step-by-step explanation:

28.

px^2 + qx + r = 0

If one root is A then the other root is 2A

We have A + 2A = -q/p   and A*2A = r/p

So 3A = -q/p  so A = -q/3p and  A^2  = r/2p  so A = √ (r / 2p)

Equating  these 2 equations:-

-q/3p =  √(r / 2p)

q^2 / 9p^2 = r / 2p

9p^2r = 2pq^2

9pr = 2q^2   (answer)


6 0
3 years ago
Two towns that are 31.5 km apart are 3 cm apart on a map. what is the scale of the map?
VLD [36.1K]

<u>Answer:</u>

1 cm : 10.5 km

<u>Step-by-step explanation:</u>

We are given that two towns are 31.5 km in real and are 3 cm apart on a map and we are to find the scale of the map.

For this, we can use the ratio method.

\frac { 3 cm } { 1 c m } = \frac { 3 1 . 5 k m } { x }

x = \frac { 3 1 . 5 \times 1 } { 3 }

x = 1 0 . 5

Therefore, the scale of the map would be 1 cm : 10.5 km.

8 0
3 years ago
Read 2 more answers
IXL geometry please help!
Sedaia [141]
<h3>Answer: 32 degrees</h3>

================================

Work Shown:

Inscribed angle theorem

arc measure = 2*(inscribed angle)

arc ABC = 2*(angle D)

arc ABC = 2*(35)

arc ABC = 70 degrees

-------------

break arc ABC into its smaller pieces

(minor arc AB)+(minor arc BC) = arc ABC

(38)+(minor arc BC) = 70

minor arc BC = 70-38

minor arc BC = 32

8 0
3 years ago
At a cafe
natta225 [31]

Answer:

cost of 1 tea= £1.08

cost of 1 coffee= £1.24

Step-by-step explanation:

Please see the attached picture for full solution

6 0
3 years ago
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