Determine parallel, perpendicular, or neither!

Mathematics

1 answer:

Leviafan [203]3 years ago

6 0

Rearrange Line 1 and Line 3’s equations in the form of y = mx + c for easier comparison.

Lines 1 and 2 are parallel, because they have the same gradient.

Lines 1 and 3, and 2 and 3 are neither, because their gradients do not multiply to form -1.
(Gradients of perpendicular lines multiply to form -1.) c

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Find the slope of the line between points A and B. Simplify your answer.

Taya2010 [7]

Answer:

-2

Step-by-step explanation:

From the given graph, the point A(1, -4) and B(-1, 0)

Slope (m) = (y2 - y1) / (x2 - x1)

x1 = 1, y1 = -4, x2 = -1 and y2 = 0

Slope (m) = (0 - (-4))/(-1 - 1)

= 4/-2

Slope = -2

Thank you.

6 0

3 years ago

Read 2 more answers

Through(-2,-3); parallel to 3x+2y=5

Vilka [71]

Step-by-step explanation:

Hey there!

Firstly find slope of the given equation.

Given eqaution is: 3x + 2y = 5.......(i)

Now;

$slope(m1) = \frac{ - coeff. \: of \: x}{coeff. \: of \: y}$

$or \: m1 = \frac{ - 3}{2}$

Therefore, slope (m1) = -3/2.

As per the condition of parallel lines,

Slope of the 1st eqaution (m1) = Slope of the 2nd eqaution (m2) = -3/2.

The point is; (-2,-3). From the above solution we know that the slope is (-3/2). So, the eqaution of a line which passes through the point (-2,-3) is;

(y-y1) = m2 (x-x1)

~ Keep all values.

$(y + 3) = \frac{ - 3}{2} (x + 2)$