The areas of two similar triangles are 72dm^2 and 50dm^2. The sum of their perimeters is 226dm. What is the perimeter of each of
1 answer:
Answer:
Per2 = 102.727 dm
Per1 = 123.272 dm
Step-by-step explanation:
We know that the area of similar triangles are related to the square of their perimeters.
This means that
(Per1^2)/(Per2^2) = Area1 / Area2
If we take the square root of the previous equation
(Per1)/(Per2) =
(Per1)/(Per2) =
(Per1)/(Per2) = 1.2
We also know that
Per1 + Per2 = 226 dm
So,
1.2*Per2 + Per2 = 226 dm
2.2*Per2 = 226 dm
Per2 = 102.727 dm
Per1 = 1.2*Per2 = 123.272 dm
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Step-by-step explanation:
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Applying u-substitution : u = tan(θ),
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Substitute back u = tan(θ) : tan^2+1(θ)/2+1
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