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3 years ago

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It is 4 : 12 p.M. 4:12 p.M.4, colon, 12, start text, space, p, point, m, point, end text Emma's mom will be home from work in 70

7070 minutes, and Emma has gymnastics lessons at 6 : 00 p.M. 6:00 p.M.6, colon, 00, start text, space, p, point, m, point, end text How much time will Emma have between the time that her mom gets home from work and the beginning of gymnastics lessons?

1 answer:

Vaselesa [24]3 years ago

5 0

Answer:

40 Minutes.

Step-by-step explanation:

The current time = 4:12 p.M.

Emma's mom will be home from work in 70 minutes.

70 minutes = 1 hour 10 Minutes= 1: 10 Hours

$\left\begin{array}{ccccc}&4&:&12 &p.m.\\+&1&:&10&\\--&--&--&--&--\\&5&:&22&p.m\end{array}\right$

Therefore, Emma's Mom will get home by 5: 22 p.m.

Emma has gymnastics lessons at 6 : 00 p.M.

To determine how much time Emma will have between the time that her mom gets home from work and the beginning of gymnastics lessons, we simply subtract 5:22 from 6.

$\left\begin{array}{ccccc}&6&:&00 &p.m.\\-&5&:&22&\\--&--&--&--&--\\&00&:&40&\end{array}\right$

Emma will have 40 Minutes.

Khan Academy User

3 years ago

for my kahn people she is WRONG

Khan Academy User

3 years ago

WRONG WRONG WRONG AHHHHHHH

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4 years ago

Given: △ACM, m∠C=90°, CP ⊥ AM . AC:CM=3:4, MP-AP=1. Find AM.

lana [24]

Answer:

$AM=\frac{25}{7}$

Step-by-step explanation:

It is given that AC:CM = 3:4.

Therefore, let AC = 3k and CM = 4k

It is given that Δ ACM is right angled.

Therefore,

$AM^{2} =AC^{2} +CM^{2}$

$=(3k)^{2} +(4k)^{2}$

$=9k^{2} +16k^{2}$

$=25k^{2}$

AM = 5k

But, AM = MP + AP

Therefore, MP + AP = 5k --- (1)

It is given that MP - AP = 1 --- (2)

Multiply (1) and (2), we get.

(MP + AP)(MP - AP) = 5k × 1 = 5k

$MP^{2} -AP^{2} =5k$

Add and subtract $CP^{2}$ on the left side.

$MP^{2} + CP^{2} - CP^{2} -AP^{2} =5k$

$(MP^{2} + CP^{2}) - (CP^{2} +AP^{2}) =5k$ --- (3)

But, since CP ⊥ AM, Δ CMP and Δ CAP are right triangles. Therefore,

$MP^{2} +CP^{2} =CM^{2}$ and

$CP^{2} +AP^{2} =AC^{2}$

Now, (3) becomes,

$CM^{2} -AC^{2} =5k$

$(4k)^{2} -(3k)^{2} =5k$

$7k^{2} =5k$

7k = 5 or

$k=\frac{5}{7}$

AM = 5k

$=5(\frac{5}{7} )$

$=\frac{25}{7}$

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3 years ago