Using confidence interval concepts, it is found that:
a) The point estimate is the sample mean.
b) The confidence interval is: 
c) If $1411 is between the bounds of the interval yes, otherwise no.
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- At item a, it asks to provide a point estimate for the population mean, which is the sample mean

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Item b:
- In the spreadsheet, it is possible to find the <em>standard deviation for the sample</em>, thus, the t-distribution is used.
- The confidence interval will be given by:

In which:
is the sample mean.- T is the critical value, from the t-distribution, with a two-tailed area of
and n-1 degrees of freedom. - s is the standard deviation for the sample.
- n is the sample size.
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Item c:
We have to check if 1411 is between
and
.
- If it is, the interval includes the National Average, otherwise, it does not.
A similar problem is given at brainly.com/question/24232455
Answer:
<h3>The ratio of technicians to all helpers is 11 : 7, or

or 11 to 7.</h3>
Step-by-step explanation:
- Given that there are 7 ushers and 11 technicians helping at the Harper Middle School fall play.
- Let x be the number of ushers ( or helpers ).
- Therefore x=7 helpers.
- Let y be the number of technicians.
- Therefore y=11 technicians.
<h3>To find the ratio of technicians to all helpers :</h3>
That is to find the ratio of y to x.
We can write the ratio of technicians to all ushers(helpers) as y : x
Which implies that 11 : 7, (since y=11 and x=7)
Or
or 11 to 7
<h3>The ratio of technicians to all helpers is 11 : 7, or

or 11 to 7</h3>
Answer:
85.11
Step-by-step explanation:
Answer:
<h2>
Area of the regular octagon is approximately 102ft²</h2>
Step-by-step explanation:
Given the radius and length of a side of regular octagon as shown;
radius = 6ft and length of side = 4.6ft
Area of a regular octagon is expressed as
where a is the length of one side. Given a = 4.6ft
Area = 

Area of the regular octagon is approximately 102ft²
let me know if the propositions they gave don't match with mine.
thanks