Question

Find four consecutive integers whose sum is 114.

Answer 1

27, 28, 29 and 30

consecutive integers have a difference of 1 between each one

let n be the first integer then the next three are

n + 1, n + 2 and n + 3

hence n + n + 1 + n + 2 + n + 3 = 114

4n + 6 = 114

subtract 6 from both sides of the equation

4n = 114 - 6 = 108

divide both sides by 4

n = $\frac{108}{4}$ = 27

n = 27, n+ 1 = 28, n + 2 = 29, n + 3 = 30

the consecutive integers are 27, 28, 29 and 30