18q+18=180
-18. -18
18q=162
/18. /18
q=9
3q=27
Answer:
Step-by-step explanation:
f(x)=2(x-2)²-5
f(x)=2(x²-4x+4)-5
f(x)=2x²-8x+3
You add two equations together to eliminate a variable. This particular problem is nice, because it's already setup to eliminate X.
3x - 4y = 9
<span>-3x + 2y = 9
</span>
When we add these two together, 3x - 3x cancels each other out, leaving us with 0x, or nothing.
We continue with -4y + 2y (leaves us with -2y) and 9+9 (18).
-2y = 18
18/-2 = -9.
Now we have y = -9, and we can go back into the problems to solve for x.
<span>3x - 4(-9) = 9
</span>
3x + 36 = 9.
3x = -27
x = -9.
Confirm with the final equation:
-3(-9) + 2(-9) = 9
27 - 18 = 9
9 = 9 --- Confirmed.
Answer:
We have the following equation: y = 36 - x. And we need to find which of the following points belong to the graph:
If any of the points belong to the equation, then the equality will be met.
Then:
7 = 36 - (-13)
7 = 36 + 13
7 = 49 ❌
1 = 36 - (-35)
1 = 71❌
5 = 36 - 11
5 = 25 ❌
3 = 36 - 27
3 = 9 ❌
None of the points belong to the graph. Therefore, all points are NOT on the grah of p(x) = 36 - x.
