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artcher [175]
4 years ago
6

3 letters start from X​

Chemistry
2 answers:
Kryger [21]4 years ago
5 0

Answer:

  • xxx
  • xxy
  • xxv  
  • xix  
  • xxi
  • xyy  
  • xcv
  • xlv
  • xvi
  • xiv
  • xtc
  • xci
  • xcl
  • xii  
  • xis
  • xia
  • xli

Explanation:

MAXImum [283]4 years ago
5 0

Answer:

<em>xanthophyll </em>

<em>xenobiotic</em>

<em>xenon </em>

<em>X group </em>

<em>x-rays</em>

<em>x-ray tube </em>

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Stolb23 [73]
Sorry i cant even read that
7 0
3 years ago
Is pluto a planet CER
ANEK [815]
This has been an ongoing debate between scientists and astrologers. It is actually classified as a dwarf planet.

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~Brooke
4 0
3 years ago
If 8.00 g NH4NO3 is dissolved in 1000 g of water, the water decreases in temperature from 21.00 degrees Celsius to 20.39 degrees
telo118 [61]

Answer:

25.7 kJ/mol

Explanation:

There are two heats involved.

heat of solution of NH₄NO₃ + heat from water = 0

q₁  +  q₂  =  0

n  =  moles of NH₄NO₃  =  8.00 g NH₄NO₃  ×  1 mol NH₄NO₃/80.0 g NH₄NO₃          

∴ n =   0.100 mol NH₄NO₃

q₁ = n * ΔHsoln = 0.100 mol * ΔHsoln

m  =  mass of solution  =  1000.0 g + 8.00 g  =  1008.0 g

q₂  =  mcΔT  = 58.0 g  ×  4.184 J°C⁻¹  g⁻¹  × ((20.39-21)°C) = -2570.19 J

q₁  +  q₂  =  0.100 mol  ×ΔHsoln  – 2570.19 J  =  0

ΔHsoln  =  +2570.19 J  /0.100 mol  =  +25702 J/mol  =  +25.7 kJ/mol

7 0
4 years ago
How many moles of co2 are produced when 5.20 mol of ethane are burned in an excess of oxygen?
galben [10]
<span>2C2H6 + 7O2 = 4CO2 + 6H2O
</span>
According to the equation of the reaction of ethane combustion, ethane and carbon dioxide have following stoichiometric ratio:

n(C2H6) : n(CO2) = 1 : 2

n(CO2) = 2 x n(C2H6) 

n(CO2) = 2 x 5.2 = 10.4 mole of CO2 is formed


6 0
4 years ago
A vessel of volume 100ml contains 10% of oxygen and 90% of an unknown gas. The gases diffuses in 86 second through a small hole
swat32

The molecular weight of unknown gas : 23.46 g/mol

<h3>Further explanation</h3>

Given

A vessel contains 10% of oxygen and 90% of an unknown gas.

diffuses rate of mixed gas = 86 s

diffuses rate of O₂ = 75 s

Required

the molecular weight of unknown gas (M)

Solution

The molecular weight of mixed gas :(M O₂=32 g/mol)

\tt 0.1\times 32+0.9\times M=3.2+0.9M

Graham's Law :

\tt \dfrac{r_{O_2}}{r_{mixed~gas}}=\sqrt{\dfrac{M_{mixed}}{M_{O_2}} }\\\\\dfrac{75}{86}=\sqrt{\dfrac{3.2+0.9M}{32} }\\\\0.76=\dfrac{3.2+0.9M}{32}\\\\24.32=3.2+0.9M\\\\21.12=0.9M\rightarrow M=23.46~g/mol

7 0
3 years ago
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