Question

potassium chlorate (kclo3) decomposes into potassium chloride (kcl) and oxygen gas (o2) how many grams of oxygen can be produced from the decomposition of 7.38 moles of potassium chlorate​

Answer 1

Answer:

$m_{O_2}=354.24gO_2$

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

$2KClO_3(s)\rightarrow 2KCl(s)+3O_2(g)$

In such a way, as 7.38 moles of potassium chloride are decomposed, the resulting grams of oxygen are computed considering a 2 to 3 molar relationship in the chemical reaction:

$m_{O_2}=7.38molKClO_3*\frac{3molO_2}{2molKClO_3}*\frac{32gO_2}{1molO_2} \\\\m_{O_2}=354.24gO_2$

Best regards.

Answer 2

Consider this reaction  : 2KClO3 → 2KCl + 3O2  

Mole ratio = 3(O2) : 2(KClO3)

Number of moles of O2 = 3/2*7.38 = 11.07 mol

Number of moles of 02 = mass/molar mass

Therefore, mass = 11.07*(16*2) = 354.24 g

Note: It's mandatory to always balance the reaction at first