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3 years ago

Apply the distributive property to expand the expression. 9(2+5m)

Mathematics

2 answers:

Maslowich3 years ago

4 0

2(9+5m) is the distributive property.

ad-work [718]3 years ago

3 0

18+45m because 9x2=18 and 9x5m=45m

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Step-by-step explanation:

Slope = Δy/Δx

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2 years ago

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2 years ago

The lengths of lumber a machine cuts are normally distributed with a mean of 106 inches and a standard deviation of 0.3 inch. (

Vinvika [58]

Answer:

a) $P(X>106.11)=P(\frac{X-\mu}{\sigma}\frac{106.11-106}{0.3})=P(z>0.37)$

And we can find this probability with the complement rule:

$P(z>0.37)=1-P(z$

b) $z =\frac{106.11- 106}{\frac{0.3}{\sqrt{44}}}= 2.431$

And if we use the z score we got:

$P(z>2.431) =1-P(z$

Step-by-step explanation:

Let X the random variable that represent the lengths of a population, and for this case we know the distribution for X is given by:

$X \sim N(106,0.3)$

Where $\mu=106$ and $\sigma=0.3$

Part a

We are interested on this probability

$P(X>106.11)$

And we can use the z score formula given by:

$z=\frac{x-\mu}{\sigma}$

And using this formula we got:

$P(X>106.11)=P(\frac{X-\mu}{\sigma}\frac{106.11-106}{0.3})=P(z>0.37)$

And we can find this probability with the complement rule:

$P(z>0.37)=1-P(z$

Part b

For this case we select a sample of n =44 and the new z score formula is given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score we got:

$z =\frac{106.11- 106}{\frac{0.3}{\sqrt{44}}}= 2.431$

And if we use the z score we got:

$P(z>2.431) =1-P(z$

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2 years ago

Review: To simplify an expression, combine like terms by adding or

gavmur [86]

Answer:

10b + 2

Step-by-step explanation:

To simplify this expression. 10b + 7 - 3 - 2 use the sample you demonstrated above to simplify it

10b + 7 -3 -2

combine the like terms

10b + 7 - 5

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3 years ago

Mark’s food for lunch cost $12. The restaurant added a 5 percent sales tax, $0.60, to the bill. Mark wants to pay a 20 percent t

kotykmax [81]

12+.60+ 12.60

12.60*20%

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Tip should be around $2.52

Hope this helped :)

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3 years ago

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