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AlexFokin [52]
3 years ago
14

How much is 3/4 of 12

Mathematics
2 answers:
mart [117]3 years ago
6 0
9....

hope this helps :)

trasher [3.6K]3 years ago
4 0
When you see the word "of" in an algebraic expression or equation, replace it with (×).

3/4 of 12 =
3/4 × 12 =
36/4 = 9
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Problem 7

(45 pages)/(90 min) = 1/2 page per min, i.e. 1 page per 2 minutes

(60 pages)(120 min) = 1/2 page per min

Both lead to the same result, so yes they are proportional.

Their reading speed is identical.

<h3>Answer: True</h3>

7 0
2 years ago
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Answer is b for this question
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3 years ago
A student uses the method of successive approximations to estimate a positive solution of f(x) = g(x), where f(x) = x2 + 10 and
serious [3.7K]

Answer:

The next number selected should be between 2 and 3 .

Step-by-step explanation:

x. x    f(x)             g(x)

0        10               17

1           11              19

2          14              21

3          19              23

4         26             25

3.5      22.25        24

<u>2.5      16.25         22</u>

1.5       12.25        20

0.5       10.25       18

We see the pattern that it is increasing with only a unit. The last given data is mid of the last two values that is 3 and 4.

So the next value would be the mid of the next last two values that is 2 and 3 and will be 2.5

Now it is moving in the reverse direction in the same pattern  with a difference of a unit.

7 0
3 years ago
Please help me- Math Sucks &gt;:(
lorasvet [3.4K]

Answer:

4x2 and 8 divided by 4

Step-by-step explanation:

I love math !

6 0
3 years ago
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List all possible rational roots. Then use synthetic division to confirm which rational roots exist:
Kisachek [45]

Answer:

\boxed{(1) \, x = \, \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10; (2) \, x = -2}

Step-by-step explanation:

2x³+ 6x² - x - 10 = 0

(1) Possible roots

The Rational Roots Theorem states that, if a polynomial has any rational roots, they will have the form p/q, where p is a factor of the constant term  and q is a factor of the leading coefficient.

\text{Possible rational root} = \dfrac{ p }{ q } = \dfrac{\text{factor of constant term}}{\text{factor of leading coefficient}}

In your function, the constant term is -10 and the leading coefficient is 2, so

\text{Possible root} = \dfrac{\text{factor of 10}}{\text{factor of 2}}

Factors of 10 = ±1, ±2, ±5, ±10

Factors of 2 = ±1, ±2

\text{Possible roots are } \large \boxed{\mathbf{x = \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10}}

(2) Synthetic division

Rather than work through all 12 possibilities, I will do one that works.

\begin{array}{r|rrrr}-2 & 2 & 6 & -1 & -10\\& & -4& -4 & 10\\& 2 & 2& -5 & 0\\\end{array}

So, x = -2 is a root, and the quotient is 2x² + 2x - 5.

(3) Check for other rational roots

2x² + 2x - 5 = 0

D = b² - 4ac =2²- 4(2)(-5) = 4 + 40 = 44

√44 = 2√11, which is irrational.

Since irrational roots come in pairs, the cubic equation has two real, irrational roots and one rational root at x = -2.

6 0
3 years ago
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