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2 years ago

How much is 3/4 of 12

Mathematics

2 answers:

mart [117]2 years ago

6 0

9....

hope this helps :)

trasher [3.6K]2 years ago

4 0

When you see the word "of" in an algebraic expression or equation, replace it with (×).

3/4 of 12 =
3/4 × 12 =
36/4 = 9

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QUESTION 8 The probability of concluding that assignable variation exists when only random variation is present is: (I) the prob

Juliette [100K]

Answer:

I, II, and IV

Step-by-step explanation:

(I) the probability of a Type I error.

(II) known as the alpha risk.

(IV) the sum of probabilities in the two tails of the normal distribution.

3 0

2 years ago

You work at a fruit stand. You are putting fruit baskets together. You have 30 oranges, 24 bananas, 42 apples, and 12 peaches. W

vovikov84 [41]

Answer:

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Step-by-step explanation:

5 0

2 years ago

Solve 3(4m - 6) = 12 and explain each step

Studentka2010 [4]

Distribute the 3 to 4m and 6. this makes 12m-18=12
now add 18 to both sides.
12m=30
now divide by 12
m=30/12

3 0

2 years ago

The number of men and women participating in the Winter Olympic Games has been steadily increasing in recent years. In the 19th

Montano1993 [528]

Using a system of equations, it is found that the correct option is:

A) 1389x+1660y=787x+1121y.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, considering the amounts in each olympics(1389 men and 787 women participated on the 19th, 1660 men and 1121 women in the 22th), the system is:

A) 1389x+1660y=787x+1121y.

More can be learned about a system of equations at brainly.com/question/24342899

6 0

2 years ago

A random variable X follows the uniform distribution with a lower limit of 670 and an upper limit of 750.a. Calculate the mean a

DENIUS [597]

You can compute both the mean and second moment directly using the density function; in this case, it's

$f_X(x)=\begin{cases}\frac1{750-670}=\frac1{80}&\text{for }670\le x\le750\\0&\text{otherwise}\end{cases}$

Then the mean (first moment) is

$E[X]=\displaystyle\int_{-\infty}^\infty x\,f_X(x)\,\mathrm dx=\frac1{80}\int_{670}^{750}x\,\mathrm dx=710$

and the second moment is

$E[X^2]=\displaystyle\int_{-\infty}^\infty x^2\,f_X(x)\,\mathrm dx=\frac1{80}\int_{670}^{750}x^2\,\mathrm dx=\frac{1,513,900}3$

The second moment is useful in finding the variance, which is given by

$V[X]=E[(X-E[X])^2]=E[X^2]-E[X]^2=\dfrac{1,513,900}3-710^2=\dfrac{1600}3$

You get the standard deviation by taking the square root of the variance, and so

$\sqrt{V[X]}=\sqrt{\dfrac{1600}3}\approx23.09$

8 0

2 years ago