320
I am positive it's correcf
Hello Friend,here is the solution for your question
<span>so the given function is </span>
y= √(-2cos²x+3cosx-1)
i.e = √[-2(cos²x-3/2+1/2)]
i.e = √[-2(cosx-3/4)²-9/16+1/2]
i.e. = √[-2(cos-3/4)²-1/16]
i.e. = √[1/8-3(cosx=3/4)²]-----------(1)
Now here in this equation is this quantity :-
<span>(cosx=3/4)²----------------(2) is to it's minimum value then the whole equation </span>
<span>i.e. = √[1/8-3(cosx=3/4)²] will be maximum and vice versa </span>
And we know that cosx-3/4 will be minimum if cosx=3/4
<span>therefore put this in (1) we get </span>
(cosx=3/4)²=0 [ cosx=3/4]
<span>hence the minimum value of the quantity (cosx=3/4)² is 0 </span>
<span>put this in equation (1) </span>
we get ,
i.e. = √[1/8-3(cosx=3/4)²]
=√[1/8-3(0)] [ because minimum value of of the quantity (cosx=3/4)² is 0 ]
=√1/8
=1/(2√2)
<span>this is the maximum value now to find the minimum value </span>
<span>since this is function of root so the value of y will always be ≥0 </span>
<span>hence the minimum value of the function y is 0 </span>
<span>Therefore, the range of function </span>y is [0,1/(2√2)]
__Well,I have explained explained each and every step,do tell me if you don't understand any step._
Answer:
lw + 
× π × 
⇒ Answer D is correct
Step-by-step explanation:
First, let us find the area of the semi-circle.
Area = × π × r²
<u>Given that,</u>
diameter of the semi-circle is ⇒ <em>l</em>
∴ radius ⇒ <em>l / 2</em>
<u>Let us find it now.</u>
Area = × π × r²
Area = × π ×
<u> </u>
Secondly, let us find the area of the rectangle.
Area = length × width
<u>Given that,</u>
length ⇒ <em>l</em>
width ⇒ w
<u>Let us find it now.</u>
Area = length × width
Area = l ×w
Area = lw
<u> </u>
And now let us <u>find the total area.</u>
Total area = Area of the rectangle + Area of the semi - circle
Tota area = lw + × π ×
Answer:
can be fourth one cause it starts at 2 on y axis. ( fourth option)
Step-by-step explanation:
can't be the first one cause it starts at origin
can't be second one cause it starts at -2 on x axis
can't be third on cause it starts on 2 on x axis
can't be fifth cause it starts on -2 on y axis.
Answer:
b. PQ
Step-by-step explanation:
