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daser333 [38]
3 years ago
15

Use the equation below to find T, if w=84, m= 7, and a = 5T=w-maT = 1-1 ?​

Mathematics
1 answer:
mart [117]3 years ago
3 0

Answer:

T = 49

Step-by-step explanation:

T = w - ma \\  \hspace{10 pt} = 84 - 7 \times 5 \\ \hspace{10 pt}  = 84 - 35 \\  \hspace{10 pt} = 49 \\

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List the 5 equivalent fractions for 2/5
salantis [7]

Answer:

Step-by-step explanation:

2/5= 4/10=8/20=16/40=32/80=64/160

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3 years ago
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Tony was Challenged to a half-court shooting competition. For every half-court shot that he makes, he will earn 20 points. For e
Mkey [24]

Answer:

Tony make 4 half-court shots and misses 16 half-court shots.

Step-by-step explanation:

Given:

Points earned for every successful, half-court shots = 20

Points deducted for missing the shots = 5 or -5

Total number of shots in the game = 20

Final points earned by Tony = 0

According to the question:

Let the number of successful half-court shot be x

And the number of shots missed be 20-x

So,

In terms of points we can re-write it as:

⇒ 20(x)-5(20-x) =0

⇒ 20x-100+5x=0

⇒ 25x-100=0

⇒ 25x-100+100=100

⇒ 25x=100

⇒ \frac{25x}{25} =\frac{100}{25}

⇒ x=\frac{100}{25}

⇒ x=4

Tony make 'x' shots that is 4 and the number of shot he missed is (20-x) =(20-4)=16

6 0
4 years ago
In angle PQR, angle P = (4x – 14)º, angle Q = (5x + 6)", and angle R= (x - 2)°. Find<br> angle R.
vekshin1

we have: ∠P + ∠Q + ∠R = 180°

<=> (4x – 14)º + (5x + 6)° + (x - 2)° = 180°

<=> 4x – 14 + 5x + 6 + x - 2 = 180°

<=> 10x - 10 = 180°

<=> 10x = 190

<=> x = 19°

So: ∠R = (x - 2)° = (19 - 2)° = 17°

ok done. Thank to me :>

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2 years ago
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Murrr4er [49]
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5/6x+290/78
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7 0
3 years ago
Assume that lines that appear to be tangent are tangent. O is the center of the circle. What is the value of x?
Mashcka [7]

9514 1404 393

Answer:

  x = 20, or 125

Step-by-step explanation:

We cannot tell the angle x is intended to refer to. So, here are two answers. Choose the one you think applies.

__

The triangle that includes both marked angles is a right triangle. (The tangent meets the circle at right angles to the radius.) So, the angle x° at the external point is the complement of the marked central angle.

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If x° is referring to the exterior angle associated with the isosceles triangle within the circle, then its measure is the supplement of the interior base angle of that triangle. It is ...

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3 years ago
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