Assume that lines that appear to be tangent are tangent. O is the center of the circle. What is the value of x?
1 answer:
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Answer:
x = 20, or 125
Step-by-step explanation:
We cannot tell the angle x is intended to refer to. So, here are two answers. Choose the one you think applies.
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The triangle that includes both marked angles is a right triangle. (The tangent meets the circle at right angles to the radius.) So, the angle x° at the external point is the complement of the marked central angle.
x° = 90° -70°
x = 20
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If x° is referring to the exterior angle associated with the isosceles triangle within the circle, then its measure is the supplement of the interior base angle of that triangle. It is ...
x° = 180° -(180° -70°)/2 = 90° +70°/2
x = 125
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Answer:
1) y=⅚x -2⅓
2) y=8/3x -5
Step-by-step explanation:
<u>Point-slope form:</u>
y=mx+c, where m is the gradient and c is the y-intercept.
Parallel lines have the same gradient.
Gradient of given line=
Thus, m=⅚
Susbt. m=⅚ into the equation,
y= ⅚x +c
Since the line passes through the point (4, 1), (4, 1) must satisfy the equation. Thus, substitute (4, 1) into the equation to find c.
When x=4, y=1,
1= ⅚(4) +c
Thus the equation of the line is .
The gradients of perpendicular lines= -1.
Gradient of given line= -⅜
-⅜(gradient of line)= -1
gradient of line
= -1 ÷ (-⅜)
= -1 ×(-8/3)
=
When x=3, y=3,
Thus the equation of the line is .