Please help! Question below (:

Mathematics

1 answer:

Ket [755]2 years ago

5 0

The 3 inside angles of a triangle need to equal 180 degrees.

You are given 28 for one.

The second on is adding 58 + 77 = 135 degrees.

X = 180 - 28 - 135 = 17 degrees

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Josiah want to gp to the movies with his friends. Tickets are $8.50 plus he must play Fangalingo a $3 transaction fee for purcha

ss7ja [257]

Answer:

The equation that represents the number of tickets that Josiah can buy with $45.50

3 + 8.50x = 45.50

The number of number of tickets that Josiah can buy with $45.50 is 5 ticketa

Step-by-step explanation:

Let the number of tickets be represented by x

Tickets are $8.50 plus he must play Fangalingo a $3 transaction fee for purchasing the tickets online.

The equation that represents the number of tickets that Josiah can buy with $45.50

$3 + $8.50 × x = $45.50

3 + 8.50x = 45.50

Solving further for x

3 + 8.50x = 45.50

8.50x = 45.50 - 3

8.50x = 42.50

x = 42.50/8.50

x = 5

Hence, the number of number of tickets that Josiah can buy with $45.50 is 5 ticketa

3 0

3 years ago

The table lists how poverty level income cutoffs (in dollars) for a family of four have changed over time. Use the midpoint for

frez [133]

The poverty level cutoff in 1987 to the nearest dollar was $10787.

<h3>How to find a midpoint?</h3>

The midpoint as the point that divides the line segment exactly in half having two equal segments. Therefore, the midpoint presents the same distance between the endpoints for the line segment. The midpoint formula is: $\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)$ .

For solving this exercise, first you need plot the points in a chart. See the image.

Your question asks to approximate the poverty level cutoff in 1987 to the nearest dollar using the midpoint formula. Note that the year 1987 is between 1980 and 1990, thus you should apply the midpoint formula from data for this year (1987).

$\mathrm{Midpoint\:of\:}\left(1980,8429),\:\left(1990,13145):\quad \left(\frac{1990+1980}{2},\:\:\frac{13145+8429}{2}\right)\\\\ \\$

$\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\left(\frac{1990+1987}{2},\:\frac{13145+3843}{2}\right)\\ \\ =\left(\frac{3977}{2},\:\frac{21574}{2}\right)$

$\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\=(\frac{3977}{2},10787)$

The answer for your question will be the value that you calculated for the y-coordinate. Then, the poverty level cutoff in 1987 to the nearest dollar was $10787.

Read more about the midpoint segment here:

brainly.com/question/11408596