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dem82 [27]
2 years ago
8

I will give brainliest to whoever answers first

Mathematics
2 answers:
Ulleksa [173]2 years ago
6 0

Answer:

AC : BC = 2 : 3

Step-by-step explanation:

AB : AC = 1 : 2

therefor

2(3x - 4) = 2x + 12

6x - 8 = 2x + 12

4x = 20

x = 5

-----------------

AC = 2x + 12 = 22

BC = 7x - 2 = 33

AC : BC = 22 : 33

Divide by 11

AC : BC = 2 : 3

mojhsa [17]2 years ago
4 0

2(3x - 4) = 2x + 12

6x - 8 = 2x + 12

4x = 20

x = 5

AB = 3(5) - 4 = 11

AC = 2(5) + 12 = 22

BC = 7(5) - 2 = 35 - 2 = 33

AC:BC = 22:33 = 2:3

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The complete question is:

Consider Neyman-Pearson criteria for two Cauchy distributions in one dimension

p(xlu;) i=1/πb·1/ 1 + (ₓ₋ₐ₁/b)²        i=1,2

Assume a zero one error loss and for simplicity a₂>a₁ the same "width" b and equal priors

1) Suppose the maximum acceptable error rate for classifying pattern that actually in ω₁ as if it were in ω₂ in E₁. Determine the decision boundary terms of the variables given.

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3) What is the overall error rate under zero-one loss?

4) Apply your results to the specific case b = 1 and a₁ = -1, a₂ = 1 and E₁= 0.1.

5) Compare your result to the Bayes error rate (i.e , without the Neyman- Pearson conditions)

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