2:3:5 _ _ _ 3 2 8 find ratio

If you have an if/else if/else code sequence with 4 blocks, what is the minimal number of input values that you should use to te

yawa3891 [41]

Answer:

4 is the correct answer for the above question.

Explanation:

If the if-else sequence has 4 blocks then it will be designed like if, else-if, else-if and then else which made 4 blocks which are as follows:-

The first block is an if block.
Then the second block is an else-if block.
The third block is also else-if block and
The fourth block else blocks.

So there is a need of 4 value (one value for each case) to test the application which is defined in the above scenario.
It is because when the first if statement is false then the first else-if statement is executed and when the first else statement is false then the second else-if statement is executed and when it is false then the else statement will executed.

7 0

3 years ago

We have said that the average number of comparisons need to find a target value in an n-element list using sequential search is

bija089 [108]

Answer:

Part a: If the list contains n elements (where n is odd) the middle term is at index (n-1)/2 and the number of comparisons are (n+1)/2.

Part b: If the list contains n elements (where n is even) the middle terms are at index (n-2)/2 & n/2 and the number of comparisons are (n+2)/2.

Part c: The average number of comparisons for a list bearing n elements is 2n+3/4 comparisons.

Explanation:

Suppose the list is such that the starting index is 0.

Part a

If list has 15 elements, the middle item would be given at 7th index i.e.

there are 7 indices(0,1,2,3,4,5,6) below it and 7 indices(8,9,10,11,12,13,14) above it. It will have to run 8 comparisons to find the middle term.

If list has 17 elements, the middle item would be given at 8th index i.e.

there are 8 indices(0,1,2,3,4,5,6,7) below it and 8 indices(9,10,11,12,13,14,15,16) above it.It will have to run 9 comparisons to find the middle term.

If list has 21 elements, the middle item would be given at 10th index i.e.

there are 10 indices (0,1,2,3,4,5,6,7,8,9) below it and 10 indices (11,12,13,14,15,16,17,18,19,20) above it.It will have to run 11 comparisons to find the middle term.

Now this indicates that if the list contains n elements (where n is odd) the middle term is at index (n-1)/2 and the number of comparisons are (n+1)/2.

Part b

If list has 16 elements, there are two middle terms as one at would be at 7th index and the one at 8th index .There are 7 indices(0,1,2,3,4,5,6) below it and 7 indices(9,10,11,12,13,14,15) above it. It will have to run 9 comparisons to find the middle terms.

If list has 18 elements, there are two middle terms as one at would be at 8th index and the one at 9th index .There are 8 indices(0,1,2,3,4,5,6,7) below it and 8 indices(10,11,12,13,14,15,16,17) above it. It will have to run 10 comparisons to find the middle terms.

If list has 20 elements, there are two middle terms as one at would be at 9th index and the one at 10th index .There are 9 indices(0,1,2,3,4,5,6,7,8) below it and 9 indices(11,12,13,14,15,16,17,18,19) above it. It will have to run 11 comparisons to find the middle terms.

Now this indicates that if the list contains n elements (where n is even) the middle terms are at index (n-2)/2 & n/2 and the number of comparisons are (n+2)/2.

Part c

So the average number of comparisons is given as

((n+1)/2+(n+2)/2)/2=(2n+3)/4

So the average number of comparisons for a list bearing n elements is 2n+3/4 comparisons.

6 0

3 years ago

Is there actually a difference between left and right twix

olga2289 [7]

One has more caramel and one has more cookie

6 0

2 years ago

Is there a link between the fields of multimedia and animation?

PtichkaEL [24]

They're (Almost) the same thing, Silly!

4 0

3 years ago

does anyone know how to access restricted websites by securly? im not trying to access anything weird they literally blocked spo

Aleksandr [31]

Answer:

Unblock websites using a VPN. Using a VPN is the easiest and most reliable way to get around content blocks and unlock the URL you want. …

Unblock websites using Tor. …

Unblock websites using a web proxy. …

Unblock websites using a proxy extension.

Explanation:

Have you tried those? Otherwise the next thing is to log in and unblock it, but you dont have the log in....

7 0

2 years ago

2:3:5_ _ _3 2 8find ratio​

2:3:5_ _ _3 2 8find ratio