Why is a memory hierarchy of different memory types used instead of only one kind of memory?
1 answer:
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Answer:
Following are the code to this question:
#include<stdio.h>//defining header file
int AND(int x,int y) //defining a method AND that hold two variable in its parameter
{
if(x==1 && y==1)//defining if block to check x and y value is equal to 1
{
return 1;//return value 1
}
else //defining else block
{
return 0;//return value 0
}
}
int OR(int x,int y)//defining method OR that hold two variable in its parameter
{
if(x==0&&y==0)//defining if block to check x and y value is equal to 1
{
return 0;//return value 0
}
else //defining else block
{
return 1;//return value 1
}
}
int main()//defining main method
{
int a,b,c;//defining integer variable
int k=1;//defining integer variable k that holds a value 1
while(k<=8)//defining while loop for 8 time input
{
printf("Please insert 3 numbers in (0 0r 1):\n ");//print message
scanf("%d%d%d", &a, &b, &c);//input value
k++;//increment the value of k by 1
printf("value: %d\n",AND(OR(a,b),c));
}
return 0;
}
Output:
please find the attachment.
Explanation:
In the above-given C language code two methods "AND and OR" is declared, holds two integer variable "x and y" in its parameters, inside the method a conditional it used that can be defined as follows:
- In the AND method, inside a conditional statement, if block check x and y both value is same that is 1 it will return 1 or it will goto else block in this it will return value 0.
- In the OR method, inside a conditional statement, if block check x and y both value is the same, that is 0 it will return 0 or it will goto else block in this it will return value 1.
- In the main method, four integers "a,b,c, and k" is declared in which variable "a, b, c" is used in the loop for 8 times input values from the user and print method is used to call the method and prints its return values.
Answer:
The interval over which the graph is decreasing is;
(-∞, -3)
Explanation:
The given function is f(x) = 2·(x + 3)² + 2
By expanding the function, we have;
2·x² + 12·x + 20
From the characteristics of a quadratic equation, we have;
The shape of a quadratic equation = A parabola
The coefficient of x² = +2 (positive), therefore the parabola opens up
The parabola has a minimum point
Points to the left of the minimum point are decreasing
The minimum point is obtained as the x-coordinate value when f'(x) = 0
∴ f'(x) = d(2·x² + 12·x + 20)/dx = 4·x + 12
At the minimum point, f'(x) = 4·x + 12 = 0
∴ x = -12/4 = -3
Therefore;
The graph is decreasing over the interval from -infinity (-∞) to -3 which is (-∞, -3)
Please find attached the graph of the function created with Microsoft Excel
The graph is decreasing over the interval (-∞, -3).
