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Tamiku [17]
3 years ago
6

Joshua went to the hardware store and bought 4 yellow ropes. The total

Mathematics
1 answer:
shusha [124]3 years ago
5 0

Answer:

15.55m

Step-by-step explanation:

<u>62</u><u>.</u><u>2</u>

4

= 15.55m

Therefore, each rope is 15.55m

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If an item is marked up 15% and the new cost is 155.25 what was the original price
Dmitry [639]
(1-0.15)=0.85
0.85 (155.25)=131.962
    estimated answer
131.962 is about $132.00
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3 years ago
Derman says, "I'm halfway through reading my book.if I read another 84 pages, I'll be two thirds of the way through my book." ho
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Use lagrange multipliers to find the shortest distance, d, from the point (4, 0, −5 to the plane x y z = 1
Varvara68 [4.7K]
I assume there are some plus signs that aren't rendering for some reason, so that the plane should be x+y+z=1.

You're minimizing d(x,y,z)=\sqrt{(x-4)^2+y^2+(z+5)^2} subject to the constraint f(x,y,z)=x+y+z=1. Note that d(x,y,z) and d(x,y,z)^2 attain their extrema at the same values of x,y,z, so we'll be working with the squared distance to avoid working out some slightly more complicated partial derivatives later.

The Lagrangian is

L(x,y,z,\lambda)=(x-4)^2+y^2+(z+5)^2+\lambda(x+y+z-1)

Take your partial derivatives and set them equal to 0:

\begin{cases}\dfrac{\partial L}{\partial x}=2(x-4)+\lambda=0\\\\\dfrac{\partial L}{\partial y}=2y+\lambda=0\\\\\dfrac{\partial L}{\partial z}=2(z+5)+\lambda=0\\\\\dfrac{\partial L}{\partial\lambda}=x+y+z-1=0\end{cases}\implies\begin{cases}2x+\lambda=8\\2y+\lambda=0\\2z+\lambda=-10\\x+y+z=1\end{cases}

Adding the first three equations together yields

2x+2y+2z+3\lambda=2(x+y+z)+3\lambda=2+3\lambda=-2\implies \lambda=-\dfrac43

and plugging this into the first three equations, you find a critical point at (x,y,z)=\left(\dfrac{14}3,\dfrac23,-\dfrac{13}3\right).

The squared distance is then d\left(\dfrac{14}3,\dfrac23,-\dfrac{13}3\right)^2=\dfrac43, which means the shortest distance must be \sqrt{\dfrac43}=\dfrac2{\sqrt3}.
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OHHHHHHH..........OK

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True or false. A binomial,where both terms are perfect squares, will always factor
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Answer:true

Step-by-step explanation:

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