Let p (x) = 4x^4-13x^2-2x
The zero of x-2 is 2
putting x = 2 in p (x), we get,
p (2) = 4×2^4-13×2^2-2×2
= 64 - 52 - 4
= 64 - 56
= 8
Therefore, remainder = 8
Answer:
4
Step-by-step explanation:
I don’t really know what this means
Answer:
number less than 3=1 and 2
so 2/6 = 1/3 in lowest terms
then rolling a 6 =
there is only one 6 so it will be 1/6
I hope I helped
Answer:
It is the second graph.
Step-by-step explanation:
