<h3>
Answer: Choice C, 2/3</h3>
============================================
Work Shown:
A = # of candies that are not green
A = (# of red)+(# of yellow)+(# of blue)
A = 25+15+20
A = 60
B = # of candies total
B = (# of red)+(# of green)+(# of yellow)+(# of blue)
B = 25+30+15+20
B = 90
P(not green) = probability of selecting candy that is not green
P(not green) = (# of candies not green)/(# of candies total)
P(not green) = A/B
P(not green) = 60/90
P(not green) = (2*30)/(3*30)
P(not green) = 2/3
Look all you have to do is with each question draw a line to the answer I am going to help you. Mark the 3rd question with answer A Mark the second question with b and the first one C I might be wrong with the first one. Hope this helps
Thank you sa points lab you
Respuesta:
0,9 veces
Explicación paso a paso:
Deje que la cantidad en la cuenta de Martha se denote como x, que es la cantidad en la cuenta = x
Porcentaje retirado para transporte = 10%
El porcentaje total siempre será del 100%
Por lo tanto, si se retira el 10%, entonces; el porcentaje restante es:
Porcentaje total: porcentaje gastado en transporte
(100% - 10%) * monto en cuenta
90% * x = 0,9 * x = 0,9x
Saldo de cuenta nueva = 0.9x
We need to expand the square binomial and then multiply:
<span>3x(x + 3)^2
= 3x(x + 3)</span>(x + 3<span>)
= 3x(x^2 + 6x + 9)
= 3x^3 + 18x^2 + 27x</span>
