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Nataly_w [17]
3 years ago
11

Kareem buys candy that costs $4 per pound. He will spend at most $48 on candy. What are the possible numbers of pounds he will b

uy?
Mathematics
2 answers:
lesantik [10]3 years ago
5 0

Answer:

12 lbs

Step-by-step explanation:

48/4 =12

mel-nik [20]3 years ago
4 0

We know that the candy costs $4 per pound

We also know that he will only spend up to $48

We can represent this as an equation:

4x = 48

Where as x = number of pounds

Solve the equation to find how many pounds he can buy.

4x = 48

Divide both sides by 4

x = 12

This means that Kareem can buy 12 pounds

Answer:

12 pounds

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Try to fill in the missing numbers
GrogVix [38]

9514 1404 393

Answer:

  [[274][895][136]]

Step-by-step explanation:

Starting with the middle row, we need a product of two single-digit numbers that is between 53-1 = 52 and 53-9 = 44. Possible products are 5×9=45 and 6×8=48. This means the number in the middle position in the left column must be 8 or 5.

The middle number in the left column cannot be 5, because we must be able to get -5 by subtracting that number from a sum that is at least 3 = 1+2. So, the middle number in the left column is 8, the other two numbers in that column are 1 and 2, and the other two numbers in the middle row are 5 and 9.

There is no product of single-digit numbers that is 30-1 = 29, so the upper left number must be 2, and the bottom left number must be 1. The other two numbers on the top row must be 4 and 7, so that row's equation is 2+4×7=30.

The only remaining digits are 3 and 6. In order to have -3 on the bottom row, the equation there must be 1×3-6 = -3. Then the middle digit must be divisible by 3, so must be 9.

Our solution is ...

row 1: 2 + 7 × 4 = 30

row 2: 8 + 9 × 5 = 53

row 3: 1 × 3 - 6 = -3

And that makes the column equations be ...

col 1: 2 - 8 + 1 = -5

col 2: 7 + 9 / 3 = 10

col 3: 4 × 5 - 6 = 14

6 0
3 years ago
Will give 5 star, thanks, and brainliest for correct answers
algol13
1) X=159
2) BCD=103
3) DCH=89
im pretty sure


7 0
3 years ago
What are the solutions of the equation (x−13)2=400?
Slav-nsk [51]

Answer:

<h2>        x = −7  and  x = 33</h2>

Step-by-step explanation:

(x-13)^2=400\\\\ (x-13)^2=(\pm20)^2\\\\x-13=20\quad\vee\quad x-13=-20\\\\x=33\qquad\vee\qquad x=-7

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3 years ago
PLEASE I REALLY NEED HELP&gt; DONT SKIP. NO LINKS PLEASE. BRANLIEST WILL BE GIVEN
LiRa [457]

Answer:

A. 165 ft²

Step-by-step explanation:

volume = (½×5×6) x 11

= 15 × 11

= 165 ft²

8 0
3 years ago
Read 2 more answers
You saved $20,000.00 and want to diversify your monies. You invest 45% in a Treasury bond for 3 years at 4.35% APR compounded an
Maru [420]

Compound Interest

A total of $20,000 is invested in different assets.

45% is invested in a Treasury bond for 3 years at 4.35 APR compounded annually.

For this investment, the principal is P = 0.45*$20,000 = $9,000.

The compounding period is yearly, thus the interest rate is:

i = 4.35 / 100 = 0.0435

The duration (in periods) is n = 3

Calculate the final value with the formula:

M=P_{}(1+i)^n

Substituting:

\begin{gathered} M=\$9,000_{}(1+0.0435)^3 \\ M=\$9,000\cdot1.136259062875 \\ M=\$10,226.33 \end{gathered}

The second investment is a CD at 3.75% APR for 3 years compounded annually. The parameters for the calculations are as follows:

P = 15% of $20,000 = $3,000

i = 3.75 / 100 = 0.0375

n = 3

Calculating:

\begin{gathered} M=\$3,000_{}(1+0.0375)^3 \\ M=\$3,000\cdot1.116771484375 \\ M=\$3,350.31 \end{gathered}

The third investment is in a stock plan. The initial value of the investment is

P = 20% of $20,000 = $4,000

By the end of the first year, the stock plan increased by 8%, thus its value is:

M1 = $4000 * 1.2 = $4,800

By the end of the second year, the stock plan decreased by 4$, thus the value is:

M2 = $4,800 * 0.96 = $4,608

Finally, the stock plan increases by 6%, resulting in a final balance of:

M3 = $4,608 * 1.06 = $4,884.48

Finally, the last investment is in a savings account at 2.90% APR compounded annually for 3 years (not mentioned, but assumed).

P = $20,000 - $9,000- $3,000 - $4,000 = $4,000

i = 2.90 / 100 = 0.029

n = 3

Calculating:

\begin{gathered} M=\$4,000_{}(1+0.029)^3 \\ M=\$4,000\cdot1.089547389 \\ M=\$4,358.19 \end{gathered}

To summarize, the final balances for each type of investment at the end of the third year are:

Investment 1; $10,226.33

Investment 2: $3,350.31

Investment 3: $4,884.48

Investment 4: $4,358.19

Total balance: $22,819.32

3 0
1 year ago
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