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3 years ago

I really need help with this question

Mathematics

1 answer:

soldier1979 [14.2K]3 years ago

3 0

Answer:

the volume of the whole shape is 676.35in^3

Step-by-step explanation:

the volume of the half cylinder is 196.35in^3

the formula used to find the volume is:

V = π * r² * h / 2

the volume of the cube is 480in^3

the formula used to find the volume is:

V = L*W*H

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3 years ago

Which unit of measure is the most reasonable to measure the length from your house to the grocery store?

Inga [223]

D.miles
Because the grocery store should be a few miles from your home.

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3 years ago

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A swimming pool had 2.5 million liters of water 2million liters evaporated what percent of weather evaporated

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3 years ago

Ashley and Kristin are selling wrapping paper for a school fundraiser. Customers can buy rolls of plain wrapping paper and rolls

rodikova [14]

The cost of one roll of plain wrapping paper is $5 and one roll of shiny wrapping paper costs $16.

Step-by-step explanation:

Step 1; Assume that the cost of one roll of plain wrapping paper is $x and a roll of shiny wrapping paper costs $y. so we have the following equations from the given data

4x + 3y = 68, take this as equation 1.

9x + 2y = 77, take this as equation 2

Step 2; We multiply equation 1 with 2 and equation 2 with 3 so we can cancel out the variable y in both equations. By doing this we get

8x + 6y = 136, take this as equation 3,

9x + 2y = 77, this is equation 4.

If we subtract 4 from 3, we cancel out the y variable and can calculate the value of x.

-19x = -103 , x = $\frac{-95}{-19}$ = 5.

Step 3; Substituting this value of x in any of the previous equations we will get x's value. Here this value of y is substituted in equation 1.

4 (5) + 3y = 68, 20 + 3y = 68 , 3y = 48, y= 16.

So we have x = $5 and y = $16.

5 0

3 years ago

Again ... Commute times in the U.S. are heavily skewed to the right. We select a random sample of 500 people from the 2000 U.S.

VladimirAG [237]

Answer:

We conclude that the mean commute time in the U.S. is less than half an hour.

Step-by-step explanation:

We are given that a random sample of 500 people from the 2000 U.S. Census is selected who reported a non-zero commute time.

In this sample the mean commute time is 27.6 minutes with a standard deviation of 19.6 minutes.

Let $\mu$ = mean commute time in the U.S..

So, Null Hypothesis, $H_0$ : $\mu \geq$ 30 minutes {means that the mean commute time in the U.S. is more than or equal to half an hour}

Alternate Hypothesis, $H_A$ : $\mu$ < 30 minutes {means that the mean commute time in the U.S. is less than half an hour}

The test statistics that would be used here One-sample t-test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean commute time = 27.6 minutes

s = sample standard deviation = 19.6 minutes

n = sample of people from the 2000 U.S. Census = 500

So, the test statistics = $\frac{27.6 -30}{\frac{19.6}{\sqrt{500} } }$ ~ $t_4_9_9$

= -2.738

The value of t test statistic is -2.738.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the t table gives critical values of -1.645 at 499 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of t as -2.378 < -1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean commute time in the U.S. is less than half an hour.

4 0

3 years ago