Answer:
heyy
Step-by-step explanation:
Answer:
7.6 inches to the nearest tenth.
Step-by-step explanation:
18/24 = 3/4.
13.5 / 18 = 3/4.
This is a Geometric sequence with common ratio 3/4 or 0.75.
We need to find the fifth term of the sequence.
5th term = a1 (r)^(5 - 1)
= 24 * (0.75)^(5-1)
= 24 * 0.316406
= 7.6 inches.
For #6;
We know that there are 46% male students and 30% of them are seniors. This means that we have to assume that 30% of the male students are seniors and that 30% of the female students are seniors. Taking 30% of 46% gives us 13.8%.
For #7;
We are looking for the possibility that we choose a junior student (22%) or a sophomore student (28%). This adds up to 50% (22%+28% = 50%). That is out answer.
Answer:
Jack is 6 and Mom is 30
Step-by-step explanation:
J = Jacks age
M = Mom's age
5J = M
In 6 years, so add 6 to the age
3(J+6) = (M+6)
We have a system of 2 equations and 2 unknowns
Lets simplify the 2nd equation
3(J+6) = (M+6)
3J + 18 = M+6
Substituting M =5J
3J + 18 = 5J +6
Subtract 3J from each side
3J-3J + 18 = 5J-3J +6
18 = 2J+6
Subtract 6 from each side
18-6 = 2J+6-6
12 = 2J
Divide each side by 2
12/2 = 2J/2
6=J
Jack is 6
We still need to find Mom's age
M = 5J
= 5*6
=30
Mom is 30
Answer:

And we can calculate this with the complement rule like this:

And using the cdf we got:
![P(X>2) = 1- [1- e^{-\lambda x}] = e^{-\lambda x} = e^{-\frac{1}{2.725} *2}= 0.480](https://tex.z-dn.net/?f=%20P%28X%3E2%29%20%3D%201-%20%5B1-%20e%5E%7B-%5Clambda%20x%7D%5D%20%3D%20e%5E%7B-%5Clambda%20x%7D%20%3D%20e%5E%7B-%5Cfrac%7B1%7D%7B2.725%7D%20%2A2%7D%3D%200.480)
Step-by-step explanation:
Previous concepts
The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:
And 0 for other case. Let X the random variable of interest:

Solution to the problem
We want to calculate this probability:

And we can calculate this with the complement rule like this:

And using the cdf we got:
![P(X>2) = 1- [1- e^{-\lambda x}] = e^{-\lambda x} = e^{-\frac{1}{2.725} *2}= 0.480](https://tex.z-dn.net/?f=%20P%28X%3E2%29%20%3D%201-%20%5B1-%20e%5E%7B-%5Clambda%20x%7D%5D%20%3D%20e%5E%7B-%5Clambda%20x%7D%20%3D%20e%5E%7B-%5Cfrac%7B1%7D%7B2.725%7D%20%2A2%7D%3D%200.480)