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Vaselesa [24]
3 years ago
5

Hjbkjbkjbkjbjbjbjbjb

Mathematics
2 answers:
erik [133]3 years ago
7 0

Answer: ok ok

Step-by-step explanation:

pochemuha3 years ago
4 0
Thx for the points g
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Solve, using the substitution method. X + y = -11
sladkih [1.3K]

Answer:

A. (-6,-5)

Step-by-step explanation:

A: Correct because -6+-5=-11------True

    and 2(-6)-3(-5) is equal to -12-(-15) and a - plus a - equals a +

    so our new equation is -12+15=3-----True

  -Your welcome and I hope this helps you, please rate 5 stars =D

3 0
3 years ago
0.00098421, in standard notation to scientific notation
irinina [24]

Answer:Scientific Notation:9.8421*10^-4

Step-by-step explanation:

3 0
3 years ago
What is the largest angle of WXY?
marin [14]

Answer:

This is because the longest side in triangle WXY is side XY (15 units), therefore making the largest angle in that triangle, angle XWY, or angle W.

Step-by-step explanation:

4 0
3 years ago
Hey guys! Can you help me how to solve number 16, 18, and 20. Because I don’t understand how to solve this
maria [59]

Problem 16

<h3>Answer: i</h3>

------------------

Work Shown:

The exponent 41 divided by 4 leads to

41/4 = 10 remainder 1

The "remainder 1" means that

i^(41) = i^1 = i

The reason why I divided by 4 is because the pattern shown below

i^1 = i

i^2 = -1

i^3 = -i

i^4 = 1

repeats itself over and over. So this is a block of four items repeated forever.

=====================================

Problem 18

<h3>Answer: 1</h3>

------------------

Work Shown:

Divide 3136 over 4 to get

3136/4 = 784 remainder 0

Therefore,

i^3136 = i^0 = 1

=====================================

Problem 20

<h3>Answer: i</h3>

------------------

Work Shown:

Combine i^6*i^7 into i^13. We add the exponents here

Now divide by 4 to find the remainder

13/4 = 3 remainder 1

So, i^13 = i^1 = i

3 0
3 years ago
Christian rented his books from the internet for a price represented by the equation below. Lela rented her books from the books
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Could you add a image or message me the image, after you do that you can comment on this and I’ll come back to it.
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3 years ago
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