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3 years ago

What region was the location of a war between Russia and the allied nations of Britain in

Mathematics

1 answer:

blagie [28]3 years ago

7 0

Answer:

war fought mainly on the Crimean Peninsula between the Russians and the British, French, and Ottoman Turkish

Step-by-step explanation:

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solve for each please i really need help if u want to help me with my test and i get an a or a b i will give u 500 dollars

Len [333]

Answer:

The relation is not a function

The domain is {1, 2, 3}

The range is {3, 4, 5}

Step-by-step explanation:

A relation of a set of ordered pairs x and y is a function if

Every x has only one value of y

x appears once in ordered pairs

Examples:

The relation {(1, 2), (-2, 3), (4, 5)} is a function because every x has only one value of y (x = 1 has y = 2, x = -2 has y = 3, x = 4 has y = 5)

The relation {(1, 2), (-2, 3), (1, 5)} is not a function because one x has two values of y (x = 1 has values of y = 2 and 5)

The domain is the set of values of x

The range is the set of values of y

Let us solve the question

∵ The relation = {(1, 3), (2, 3), (3, 4), (2, 5)}

∵ x = 1 has y = 3

∵ x = 2 has y = 3

∵ x = 3 has y = 4

∵ x = 2 has y = 5

→ One x appears twice in the ordered pairs

∵ x = 2 has y = 3 and 5

∴ The relation is not a function because one x has two values of y

∵ The domain is the set of values of x

∴ The domain = {1, 2, 3}

∵ The range is the set of values of y

∴ The range = {3, 4, 5}

3 0

2 years ago

The length (in centimeters) of a typical Pacific halibut t years old is approximately f(t) = 200(1 − 0.956e−0.18t). Suppose a Pa

horsena [70]

Answer:

7.2 years

Step-by-step explanation:

$f(t) =200(1 - 0.956e^{-0.18t})$

where f(t) is the length and t is the number of years old

given the Mike measures 148 cm, we need to find out the age

So we plug in 148 for f(t) and solve for t

$148 =200(1 - 0.956e^{-0.18t})$

divide both sides by 200

$\frac{148}{200} = 1 - 0.956e^{-0.18t}$

Now subtract 1 from both sides

$-0.26= - 0.956e^{-0.18t}$

Divide both sides by -0.956

$\frac{0.26}{0.956} =e^{-0.18t}$

Now take ln on both sides

$\frac{0.26}{0.956} =e^{-0.18t}$

$ln(\frac{0.26}{0.956} )=-0.18tln(e)$

$ln(\frac{0.26}{0.956} )=-0.18t$

divide both sides by -0.18

t=7.2

So 7.2 years

5 0

3 years ago

Please help me solve the expression for “n”

Bingel [31]

Answer:

n = 2

Step-by-step explanation:

In order for the ratio to have a value of 1, the sum of exponents in the numerator must equal the sum of exponents in the denominator:

n + 7 = 9

n = 9 -7 . . . . . . subtract 7 from both sides of the equation

n = 2

___

Alternatively, you can simplify the given expression:

$\dfrac{9^n(9^7)}{9^9}=1=\dfrac{9^n}{9^2}$

Hopefully, it is clear to you that the value of n must be 2 in order to make the numerator equal to the denominator.

5 0

3 years ago

Do i have the right answer in the attachment?

Effectus [21]

Answer:

nope it would be B (1)

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Help please ......................

seropon [69]

1. 35x + 0.15y
=3500x + 15y [multiplying the equation by 100]
= 700x + 3y [dividing the equation by 5]

2. Let x be an even integer
x + (x+2) + (x+2+2)
x+x+2+x+4
3x+6

3. 1/5*(r+7) - 9s
(r+7)/5 - 9s

4. x=cows
y= goats + sheep

x= (y+140)/2

7 0

3 years ago

Read 2 more answers