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2 years ago

I need help fast please

Mathematics

2 answers:

loris [4]2 years ago

8 0

I think the answer be C? Sorry if it's wrong

levacccp [35]2 years ago

5 0

Answer:

it's

answer D

Step-by-step explanation:

$5.0 \times 10 ^{ - 4} - 3.0 \times {10}^{ - 5} \\ 0.0005 - 0.00003 \\ = 0.00047 = 4.7 \times {10}^{ - 4}$

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Find the measure of each angle. 10x - 20= 7x + 4

lara [203]

Answer:x=8 so 60 for both aswers

Step-by-step explanation:10x-7x = 4+20 -> 3x=24 -> x=8

3 0

2 years ago

Read 2 more answers

Will give Brainliest

geniusboy [140]

Answer:

The y intercept is 2

Step-by-step explanation:

Y = mx + b where b is the y intercept. Since b = 2 here, the y intercept is 2. Yes, the line crosses the y-axis at the point (0,2).

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2 years ago

An airplane travels 6111 kilometers against the wind in 9 hours and 7911 kilometers with the wind in the same amount of time. Wh

natima [27]

Answer:

Speed of the plane in still air: $779\; {\rm km \cdot h^{-1}}$ .

Windspeed: $100\; {\rm km \cdot h^{-1}}$ .

Step-by-step explanation:

Assume that $x\; {\rm km \cdot h^{-1}}$ is the speed of the plane in still air, and that $y\; {\rm km \cdot h^{-1}}$ is the speed of the wind.

When the plane is travelling against wind, the ground speed of this plane (speed of the plane relative to the ground) would be $(x - y)\; {\rm km \cdot h^{-1}}$ .
When this plane is travelling in the same direction as the wind, the ground speed of this plane would be $(x + y)\; {\rm km \cdot h^{-1}}$ .

The question states that when going against the wind ( $v = (x - y)\; {\rm km \cdot h^{-1}}$ ,) the plane travels $6111\; {\rm km}$ in $9\; {\rm h}$ . Hence, $9\, (x - y) = 6111$ .

Similarly, since the plane travels $7911\; {\rm km}$ in $9\; {\rm h}$ when travelling in the same direction as the wind ( $v = (x + y)\; {\rm km \cdot h^{-1}}$ ,) $9\, (x + y) = 7911$ .

Add the two equations to eliminate $y$ . Subtract the second equation from the first to eliminate $x$ . Solve this system of equations for $x$ and $y$ : $x = 779$ and $y = 100$ .

Hence, the speed of this plane in still air would be $779\; {\rm km \cdot h^{-1}}$ , whereas the speed of the wind would be $100\; {\rm km \cdot h^{-1}}$ .

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1 year ago

HELP PLEASE I DONT UNDERSTAND THIS AT ALL slope =

Elanso [62]

Answer:

look at the picture i have sent

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3 years ago

I'll give Brainliest!!

scoundrel [369]

Answer:

Step-by-step explanation:

The similarity statement is correct. Because they are similar, AB is equal to EF, so to find x, you do x-2=2.2. Solve that and you get x=0.2

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2 years ago