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kifflom [539]
4 years ago
7

Please help!!! will give brainliest

Physics
2 answers:
kotykmax [81]4 years ago
6 0
5.0 m per second !!!!
Yanka [14]4 years ago
3 0

Answer:

hmmm, i wanna say....5.0 m per second but im not 100% sure

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The answer is Saturn. 


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What would be the final temperature of the system if all the heat lost by the copper block were absorbed by the water in the cal
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<span>Answer: q Cu = q H2O so, (121g)(0.385 J/g-K)(100.4C-x) = (150g)(4.18 J/g-K)(x-25.1C) x= 30.3C</span>
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3 years ago
The man fire a 50-g arrow that moves at an unknown speed. It hits and embeds in a 350-g block that slides on an air track. At th
Natasha_Volkova [10]

Answer:

a)  vAix = 80 m/s

b) The assumptions and implications were:

Assume that friction between the block and the surface it rests on does not change the momentum of the system during the collision.

Assume that friction is negligible throughout the process and the system’s internal energy does not change.

Assume all the system’s kinetic energy is converted into elastic potential energy at the end of the process.

If any of the assumptions are invalid then the arrow must have been travelling initially, vAix > 80 m/s

Explanation:

Arrow embeds into block

Take in the first instance the system to be the arrow + block (isolated). Establish reference coordinate system with the +x axis running horizontally in the direction of the arrow’s motion. The initial state (i) is the arrow travelling with velocity vAix and the final state (f) is the arrow embedded in the block. Now, apply the component form of the Generalized Impulse Momentum Equation to this system:

pAi + pBi + JonA + JonB = pAf + pBf

pAix + pBix + Jx = pAfx + pBfx

mA*vAix + mB*vBix + 0 = (mA + mB)*vfx

0.05*vAix + 0 = (0.05 + 0.35)*vfx

vAix = 8*vfx        (1)

Arrow embeds into block

Now consider the next phase of motion and take as the system the arrow + block + spring. The initial state (i) is the arrow and block travelling with velocity equivalent to the final velocity from equation 1 (final state velocity in first phase becomes initial velocity in next phase);  vix’ = vfx  and the final state (f) is the arrow + block brought to rest and the spring compressed an amount, Δx = 0.1 m. Now, apply the Generalized Work Energy Principle to the system

Ei + W = Ef

Ki + Usi + W = Kf + Usf

0.5*(mA + mB)*vix’² = 0.5*k*Δx²

(0.05 + 0.35)*vfx² = 4000*(0.1)²

vfx = √(40/0.4) = 10 m/s

Substituting above back into equation 1:

vAix = 8* 10 m/s = 80 m/s

Arrow embeds into block

The assumptions and implications were:

Assume that friction between the block and the surface it rests on does not change the momentum of the system during the collision.

Assume that friction is negligible throughout the process and the system’s internal energy does not change.

Assume all the system’s kinetic energy is converted into elastic potential energy at the end of the process.

If any of the assumptions are invalid then the arrow must have been travelling initially, vAix > 80 m/s

7 0
3 years ago
An electrostatic paint sprayer has a 0.17 m-diameter metal sphere at a potential of 25.0 kV that repels charged paint droplets o
Troyanec [42]

Answer:

q=0.236uC

Explanation:

From the question we are told that:

Diameter d=0.17m

Radius r=0.17/2=>0.085

Potential E=25.0kV

Generally the equation for Potential on spere is mathematically given by

E=\frac{1}{4 \pi e_0}*\frac{q}{r}

Therefore

q=\frac{25*10^3*0.085}{\frac{1}{4 \pi e_0}}

Where

\frac{1}{4 \pi e_0}=9*10^9

Therefore

q=\frac{25*10^3*0.085}{(9*10^9}}

q=0.236uC

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