Answer:
well at the rate he goes he would be at 2.5km
Answer:
Velocity-time graph of an object moving with uniform velocity. The slope of a Velocity–time graph of an object moving in rectilinear motion with uniform velocity is straight line and parallel to x-axis when velocity is taken along y-axis and time is taken along x-axis
Answer:
Right shoe
Explanation:
Let the mass and velocity of incoming puck be m and v respectively.
Momentum of the colliding puck will be mv
In case of first case , the momentum of puck becomes zero so change in momentum after collision with left shoe
= mv - 0 = mv
If time duration of collision be t
rate of change of momentum
= mv / t
This is the force exerted by puck on the left shoe .
Now let us consider collision with right shoe
momentum after collision with right shoe
- mv
change in momentum
= mv - ( - mv ) = 2mv
If time duration of collision be t
rate of change of momentum
= 2mv / t
This is the force exerted by puck on the right shoe .
Since the force on the right shoe is more , this shoe will have greater speed
after collision.
<span>The equation for momentum is p = mv, where m is the mass of the object and v is its velocity. Through conservation of momentum, we know that the momentum of the rifle must be of the same magnitude and opposite direction to that of the bullet. Thus we can form two expressions for the respective momenta, set them equal, and solve for the recoil speed of the rifle.
718*0.0159 = vr*5.05 where vr is the rifle recoil speed.
Solving for vr = 718*0.0159/5.05 = 2.26 meters/second.</span>