Identify the solution set of the given inequality using replacement set.

Amira has 3/4 of a bag of cat food. her cat eats 3/4 lbs of a bag per week

Stels [109]

Answer:

1 week

Step-by-step explanation:

The correct question is

Amira has 3/4 of a bag of cat food .Her cat eats 3/4 of a bag per week . How many weeks will the food last ?

we know that

To determine how many weeks her food will last, we take the amount of food and divide by how much she feeds her cats.

3/4 bag ÷ 3/4 bag per week

$\frac{3}{4}: \frac{3}{4}$

Multiply in cross

$\frac{3*4}{4*3}=1\ week$

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%7B%20%20%5Cpi%20%7D%20%5Ccos%28%20%5Ccot%28x%29%20%20%20%20-%20%2

Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

$\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx$

but the integrand is even, so this is really just

$\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx$

Substitute x = 1/2 arccot(u/2), which transforms the integral to

$\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du$

There are lots of ways to compute this. What I did was to consider the complex contour integral

$\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz$

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

$\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}$

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

$\displaystyle \int_{-\infty}^\infty \frac{\cos(x)}{x^2+4} \, dx = 2\pi i {} \mathrm{Res}\left(\frac{e^{iz}}{z^2+4},z=2i\right) = \frac\pi{2e^2}$

and it follows that

$\displaystyle \int_0^\pi \cos(\cot(x)-\tan(x)) \, dx = \boxed{\frac\pi{e^2}}$

7 0

2 years ago

9 dollars for 3 cans of tuna *

Klio2033 [76]

Answer:

3 dollars for each can of tuna

Step-by-step explanation:

9-3=6

6-3=3

3-3=0

3 0

3 years ago

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Each person in a group of college students was identified by graduating year and asked when he or she preferred taking classes:

swat32

Answer:

0.615

Step-by-step explanation:

The frequency table is attached below.

We have to calculate, the probability that the student preferred morning classes given he or she is a junior.

i.e $P(\text{Morning }|\text{ Junior})$

We know that,

$P(A\ |\ B)=\dfrac{P(A\ \cap\ B)}{P(B)}$

So,

$P(\text{Morning }|\text{ Junior})=\dfrac{P(\text{Morning }\cap \text{ Junior})}{P(\text{Junior})}$

Putting the values from the table,

$\dfrac{P(\text{Morning }\cap \text{ Junior})}{P(\text{Junior})}=\dfrac{\frac{16}{143}}{\frac{26}{143}}=\dfrac{16}{26}=0.615$

3 0

3 years ago

Rachel is keeping track of how much water she drinks. On Friday, she drank two bottles of water with snacks and 5 cups of water

xeze [42]

Answer:

2 CUPS

Step-by-step explanation:

Write two equations, where "b" = bottles, and "c" = cups

2b +5c = b +7c -->

b = 2c

THERE ARE 2 CUPS IN A BOTTLE

6 0

3 years ago

Read 2 more answers