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madreJ [45]
3 years ago
5

On a map of the city, 8th Street is a line segment from point (1,4) to point (6,9). J Street is a line segment that starts at (4

,–14) and stops at (–5,4). If the city council extends 8th Street in a straight line, where will it intersect J Street?
Mathematics
1 answer:
Dominik [7]3 years ago
8 0
The intersection of 8th street and J street can be determined by setting up an equation for each line segment given the points mentioned above. Note that the equation of a line can be obtained from two points such that:

y - y1 = m(x-x1), where m = (y2-y1)/(x2-x1)

For instance, the equation for 8th street is given by: y - 4 = [(9-4)/(6-1)]*(x-1). On the other hand, the equation for J street is given by: y + 14 = [(4+14)/(-5-4)]*(x-4). Simplifying the 2 equations we get: Eqn. (1) y = x + 3 and Eqn. (2) y = -2x - 6

Solving the 2 equations simultaneously, we obtain x = -3, y = 0. Thus, if the city council extends 8th street in a straight line, it will intersect J street at (-3,0).

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The two containers are mathematically similar in shape. The larger container has a volume of 3456cm3 and a surface area of 1024c
grin007 [14]

Answer:

1458/3456 = 27/64 (simplification)

cube root of 27/64 = 3/4

square of 3/4 = 9/16

9/16 multplied by 1024 = 576.

THIS IS THE REAL WORKING AND ANSWER

Pls mark me brainliest

4 0
3 years ago
Find the value of X. Round to the<br> nearest tenth. <br> 7.4in <br> 2.4in<br> x
Darya [45]

Answer:

4.4 inches

Step-by-step explanation:

Here, we are interested in calculating the value of x.

Mathematically, a line that comes from the center of the circle and extends to a chord, divides the chord into two equal parts.

This means what we have is a right angled triangle with the radius being the hypotenuse, the half of the length of the chord as the other side of the triangle.

3.7 is half the length of the chord i.e 7.4/2

Thus;

using Pythagoras’ theorem

x^2 = 2.4^2 + 3.7^2

Pythagoras’ posited that the square of the hypotenuse is equal to the sum of the squares of the other two sides of the triangle.

Thus;

x^2 =5.76 + 13.69

x^2 = 19.45

x = √(19.45)

x = 4.41 inches which is 4.4 inches to the nearest tenth

6 0
2 years ago
Read 2 more answers
6. Blake went to the grocery store at 6:30PM, He returned to his house around 9:14PM after running
zhenek [66]
If you subtract the times periods form each you will be able to get your answer. So, 9:14-6:30 it will be 2 hours and 44 mins because from 6:30 to 7 it 30 mins, and from 7 to 9 it’s 2 hours. So far, add the two and you get 2h and 30mins and from 9 to 9:14 it’s 14 mins. So, 2h 30 mins plus 14 mins is 2h and 44mins.
5 0
3 years ago
**The following scenario is for #12, #13, and #14 on this test.** A school chorus has 90 sixth grade students and 75 seventh gra
givi [52]

Answer:

The music director can make 15 groups of performers with 6 sixth grade students and 5 seventh grade students in each group.

Step-by-step explanation:

A school chorus has 90 sixth-grade students and 75 seventh-grade students.

Factor these two numbers:

Find GCF(90,75):

Now,

Therefore, the music director can make 15 groups of performers with 6 sixth grade students and 5 seventh grade students in each group.

6 0
2 years ago
Does anyone know the answer for the question below.
8090 [49]

Answer: option C

Step-by-step explanation:

The diagram of the triangle is shown in the attached photo. The triangle is a right angle triangle ABC

Assuming the given angle is #,

Recalling the trigonometric ratio,

tan # = opposite / adjacent

If tan # = 4, it means

opposite / adjacent = 4/1

Therefore, opposite = 4 and adjacent = 1

Applying Pythagoras theorem,

Hypotenuse^2 = opposite ^2 + adjacent ^2

Hypotenuse = AC

Opposite = 4

Adjacent = 1

AC^2 = 4^2 + 1^2 = 17

AC = ± √17

To determine cos #, we would apply another trigonometric ratio,

Cos# = adjacent /hypotenuse

Cos# = 1/±√17

Cos # =-1 /√17 or 1/√17

8 0
3 years ago
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