Answer:
1458/3456 = 27/64 (simplification)
cube root of 27/64 = 3/4
square of 3/4 = 9/16
9/16 multplied by 1024 = 576.
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Answer:
4.4 inches
Step-by-step explanation:
Here, we are interested in calculating the value of x.
Mathematically, a line that comes from the center of the circle and extends to a chord, divides the chord into two equal parts.
This means what we have is a right angled triangle with the radius being the hypotenuse, the half of the length of the chord as the other side of the triangle.
3.7 is half the length of the chord i.e 7.4/2
Thus;
using Pythagoras’ theorem
x^2 = 2.4^2 + 3.7^2
Pythagoras’ posited that the square of the hypotenuse is equal to the sum of the squares of the other two sides of the triangle.
Thus;
x^2 =5.76 + 13.69
x^2 = 19.45
x = √(19.45)
x = 4.41 inches which is 4.4 inches to the nearest tenth
If you subtract the times periods form each you will be able to get your answer. So, 9:14-6:30 it will be 2 hours and 44 mins because from 6:30 to 7 it 30 mins, and from 7 to 9 it’s 2 hours. So far, add the two and you get 2h and 30mins and from 9 to 9:14 it’s 14 mins. So, 2h 30 mins plus 14 mins is 2h and 44mins.
Answer:
The music director can make 15 groups of performers with 6 sixth grade students and 5 seventh grade students in each group.
Step-by-step explanation:
A school chorus has 90 sixth-grade students and 75 seventh-grade students.
Factor these two numbers:
Find GCF(90,75):
Now,
Therefore, the music director can make 15 groups of performers with 6 sixth grade students and 5 seventh grade students in each group.
Answer: option C
Step-by-step explanation:
The diagram of the triangle is shown in the attached photo. The triangle is a right angle triangle ABC
Assuming the given angle is #,
Recalling the trigonometric ratio,
tan # = opposite / adjacent
If tan # = 4, it means
opposite / adjacent = 4/1
Therefore, opposite = 4 and adjacent = 1
Applying Pythagoras theorem,
Hypotenuse^2 = opposite ^2 + adjacent ^2
Hypotenuse = AC
Opposite = 4
Adjacent = 1
AC^2 = 4^2 + 1^2 = 17
AC = ± √17
To determine cos #, we would apply another trigonometric ratio,
Cos# = adjacent /hypotenuse
Cos# = 1/±√17
Cos # =-1 /√17 or 1/√17