<span>Let the extension of the length and width be x.
The new dimensions are: Length = 8+x
Width =3+x
Area = 104 ft squared
Area of a rectangle = Length x Width
Therefore,
(8+x)(3+x) = 104
x^2 +11x +24=104
x^2 +11x +24-104=0
x^2 +11x-80=0
Factorize using splitting the middle term method.
X^2 +16x-5x-80=0
x(x+16)-5(x+16)=0
(x-5)(x+16)=0
either x-5 = 0 or x+16=0
x=5 or x=-16
length and width measure cannot be negative.
Therefore, the extension of the length and width is 5 feet each.</span>
1. it describes what the cost would be for two medium lattes and one small latte all together.
2. it would be the first one which is 2x + y = 7.15
Step-by-step explanation:
Answer:
55.5 square feet
Step-by-step explanation:
so the dog house consists of 4 walls, two roof sections, and two triangle bits to make the roof pointy (I'm sure they have a name but I don't know what it is lol) Of the walls there would be 2 of the longer walls and 2 of the shorther ones. Knowing this we just have to add together the area of each part to find the total surface area.
So starting with the walls:
two of them are 4 feet by 2 feet.
The area of a rectangle is just length x width
so those two would have an area of 8 ft^2
and the other two are 3 feet by 2 feet so they would have an area of 6 ft^2
the roof sections are also rectangles with dimensions of 4 feet by 2.5 feet
4x2.5=10 so each side of the roof has a surface area of 10 ft^2
now the triangle parts have a base of 3 feet and a height of 2.5 feet
the formula for area of a triangle is base x height / 2
3x2.5=7.5
7.5/2= 3.75
now we add them together
8+8+6+6+10+10+3.75+3.75=55.5
so the total surface area is 55.5 square ft
The percent of students that are aged 19 years or more is determined as 84%.
<h3>One standard deviation below the mean</h3>
In a normal distribution curve 1 standard deviation below the mean is defined as follows;
- 1 std below mean : M - d = 16%
M - d = 20.6 yrs - 1.3 yrs = 19.3 years ≈ 19 years
19 years or more will occur at (M - d) + (M) + (M + 2d) = 100% - (M - d)
= 100% - 16%
= 84%
Thus, the percent of students that are aged 19 years or more is determined as 84%.
Learn more about normal distribution here: brainly.com/question/4079902
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