The first two numbers between 100 and 150 that have a HCF of 22 are 110 and 132
<h3>Highest common factors</h3>
The greatest common divisor of two or more integers, which are not all zero, is the largest positive integer that divides each of the integers.
According to the question, we are to find two numbers between 100 and
150 that have a HCF of 22.
In order to do that we will<u> multiply 22 by the values 5 and 6</u>
First number = 22 * 5 = 10
Second number = 22 * 6 = 132
Hence the first two numbers between 100 and 150 that have a HCF of 22 are 110 and 132
Learn more on HCF here; brainly.com/question/21504246
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Answer:
left, right
Step-by-step explanation:
If you use the < or ≤ symbol to compare the numbers, their left-right order is the same as on the number line. Here, we would write the ordering as ...
-21 < -20 < -19
So, we see that ...
-21 is <em>left</em> of -20 on the number line
-19 is <em>right</em> of -20 on the number line
Answer:
To solve the first inequality, you need to subtract 6 from both sides of the inequality, to obtain 4n≤12. This can then be cancelled down to n≤3 by dividing both sides by 4. To solve the second inequality, we first need to eliminate the fraction by multiplying both sides of the inequality by the denominator, obtaining 5n>n^2+4. Since this inequality involves a quadratic expression, we need to convert it into the form of an^2+bn+c<0 before attempting to solve it. In this case, we subtract 5n from both sides of the inequality to obtain n^2-5n+4<0. The next step is to factorise this inequality. To factorise we must find two numbers that can be added to obtain -5 and that can be multiplied to obtain 4. Quick mental mathematics will tell you that these two numbers are -4 and -1 (for inequalities that are more difficult to factorise mentally, you can just use the quadratic equation that can be found in your data booklet) so we can write the inequality as (n-4)(n-1)<0. For inequalities where the co-efficient of n^2 is positive and the the inequality is <0, the range of n must be between the two values of n whereby the factorised expresion equals zero, which are n=1 and n=4. Therefore, the solution is 1<n<4 and we can check this by substituting in n=3, which satisfies the inequality since (3-4)(3-1)=-2<0. Since n is an integer, the expressions n≤3 and n<4 are the same. Therefore, we can write the final answer as either 1<n<4, or n>1 and n≤3.
Answer:
B
Step-by-step explanation:
x² - 12x + 11 = 0 ( subtract 11 from both sides )
x² - 12x = - 11
To complete the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(- 6)x + 36 = - 11 + 36
(x - 6)² = 25 ( take square root of both sides )
x - 6 = ± 
= ± 5 ( add 6 to both sides )
x = 6 ± 5
Then
x = 6 - 5 = 1 ⇒ (1, 0 )
x = 6 + 5 = 11 ⇒ (11, 0 )
I think it is 1.5, sorry if i'm wrong good luck!!!
:)
