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mash [69]
3 years ago
14

!!!PLEASE ANSWER!!!

Mathematics
1 answer:
Anni [7]3 years ago
3 0

Answer:

A

Step-by-step explanation:

A rule for every right angle triangle is a^2+b^2 =c^2

but here 5^2 + 10^2 does not equal to 12^2.

Therefore the answer is A.

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I need Helppppppppppppppp with this
amid [387]

Answer:

Option A

Step-by-step explanation:

Jessica divides the ribbon in three parts out of which length of one part = 3\frac{1}{2} inches

Let the length of other two parts = x inches

Total length of whole ribbon = 12 inches

3\frac{1}{2}+x+x=12

3\frac{1}{2}+2x=12

2x=12-3\frac{1}{2}

2x=12-\frac{7}{2}

2x=\frac{24-7}{2}

2x=\frac{17}{2}

x=\frac{17}{4}

x=7\frac{1}{4} inches

Therefore, option A will be the answer.

7 0
3 years ago
Read 2 more answers
Fernando had 2 children. Each of their children had 2 children, and each of these
rjkz [21]

Answer:

4

Step-by-step explanation:

Fernando-

Child 1-     Child 2-

2 kids-      2 kids-            = 4 grandchildren for Fernando

2 kids       2 kids              These are his great grandchildren, not grandchildren.

7 0
3 years ago
Show that the line integral is independent of path by finding a function f such that ?f = f. c 2xe?ydx (2y ? x2e?ydy, c is any p
Juli2301 [7.4K]
I'm reading this as

\displaystyle\int_C2xe^{-y}\,\mathrm dx+(2y-x^2e^{-y})\,\mathrm dy

with \nabla f=(2xe^{-y},2y-x^2e^{-y}).

The value of the integral will be independent of the path if we can find a function f(x,y) that satisfies the gradient equation above.

You have

\begin{cases}\dfrac{\partial f}{\partial x}=2xe^{-y}\\\\\dfrac{\partial f}{\partial y}=2y-x^2e^{-y}\end{cases}

Integrate \dfrac{\partial f}{\partial x} with respect to x. You get

\displaystyle\int\dfrac{\partial f}{\partial x}\,\mathrm dx=\int2xe^{-y}\,\mathrm dx
f=x^2e^{-y}+g(y)

Differentiate with respect to y. You get

\dfrac{\partial f}{\partial y}=\dfrac{\partial}{\partial y}[x^2e^{-y}+g(y)]
2y-x^2e^{-y}=-x^2e^{-y}+g'(y)
2y=g'(y)

Integrate both sides with respect to y to arrive at

\displaystyle\int2y\,\mathrm dy=\int g'(y)\,\mathrm dy
y^2=g(y)+C
g(y)=y^2+C

So you have

f(x,y)=x^2e^{-y}+y^2+C

The gradient is continuous for all x,y, so the fundamental theorem of calculus applies, and so the value of the integral, regardless of the path taken, is

\displaystyle\int_C2xe^{-y}\,\mathrm dx+(2y-x^2e^{-y})\,\mathrm dy=f(4,1)-f(1,0)=\frac9e
8 0
3 years ago
How do the 2s in 12.5 and 0.912 compare?
user100 [1]

Answer:

i dont know

Step-by-step explanation:

ed

5 0
3 years ago
What is the value of this expression? PLEASE HELP!!!!
Brrunno [24]
2 X { 6 + [ 12 divided ( 3 + 1 ) ] } - 1

3 + 1 = 4 

12 divided by 4 is 3

2 X { 6 + [ 3 ] } - 1

6 + 3 = 9

2 X { 9 } - 1

9 X 2 = 18

18 - 1 = 17!

17 is the answer

I used PEMDAS

P - Parenthesis

E - Exponents

M - Multiplication

D - Division

A - Addition

S - Subtraction

[in order that your supposed to do]




5 0
3 years ago
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