Making the usual substitutions (x=r·cos(θ), y=r·sin(θ)), you have (r·cos(θ))² +4r·cos(θ) +4 + (r·sin(θ))² -4r·sin(θ) +4 = 8 r(r +4·cos(θ) -4·sin(θ)) = 0 Dividing by r then subtracting the non-r terms gives r = 4(sin(θ) -cos(θ))
-2(6-x)= 3x, the solution is find the value of x, you must apply distributive property, tho the first term, -12+2x= 3x⇒ 3x-2x= -12⇒ x = -12, the answer correct is option D
