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Andrej [43]
3 years ago
10

Write a fraction greater than 1. Everything shaded

Mathematics
1 answer:
Vlada [557]3 years ago
8 0
Any fraction greater than 1 is a numerator (top number of a fraction) that is greater than its denominator (bottom number of a fraction).

Examples: 3/2, 8/5, 8/4, etc.

As long as the number above is greater than the number below on the fraction, it is greater than 1.
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I need to find the percentage of students who ride the bus
NikAS [45]

Answer:

40%

Step-by-step explanation:

% of students drive to school

= no of students who drive/ total students× 100

=250/250+375×100

=250/625×100

=40%

4 0
3 years ago
Ill i need to know is the fraction please
murzikaleks [220]

Answer:

6/10 i think

Step-by-step explanation:

625 divided by 15 is 41.6 so i'd be 40+1+6/10

6 0
3 years ago
Read 2 more answers
I’ve been stuck on this question since beginning of my freshman year! Someone please explain how to do this please??!
dexar [7]

Hi!

There might be different variations into how anyone would approach this problem but this is by far an easy way for me.

In order to solve fractional relationships with a variable, a perfect way to solve them would be to cross multiply and make them equal to each other.

You see the part '3y+12', and when you criss cross over to the other side of the equation, you get three. Multiply that together.

When you see the part '6', when you glide diagonally, you find '4y'. Multiply this together as well. Make them equal to each other.

(<em>This is how you do cross multiplication.)</em>

You should get something like this:

3(3y+12)=6(4y)              Distribute the three on the left side and multiply. Do the same on the right.

9y+36=24y                    Now, you can combine like terms by subtracting 9y to the other side.

36=15y                           Isolate y and divide it by 15.

y=2.4

I was unclear of the answer, so I plugged in 2.4 into the original equation where the y variable was, and got the right answer, so 2.4 should be the correct one no matter how you got it.

I hope this helped!

8 0
2 years ago
)<br> 1.What is the additive of 3/8
tekilochka [14]

Answer:

3

Step-by-step explanation:

3 + (-8) - (-8)

= 3 - 8 + 8

= 3

6 0
3 years ago
The shape of the distribution of the time required to get an oil change at a 15-minute oil-change facility is unknown. However,
horsena [70]

Answer:

The mean oil-change time that would there be a 10% chance of being at or below is 15.46 minutes.

Step-by-step explanation:

We are given that records indicate that the mean time is 16.2 minutes, and the standard deviation is 3.4 minutes.

On a typical​ Saturday, the​ oil-change facility will perform 35 oil changes between 10 A.M. and 12 P.M. Assuming that data follows normal distribution.

Let \bar X = <u><em>sample mean time</em></u>

The z score probability distribution for sample mean is given by;

                          Z  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean time = 16.2 minutes

            \sigma = standard deviation = 3.4 minutes

            n = sample size = 35 oil changes

<u>Now, the mean oil-change time that would there be a 10% chance of being at or below is given by;</u>

<u></u>

          P(X \leq x) = 0.10          {where x is required mean oil-change time}

          P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \leq \frac{x-16.2}{\frac{3.4}{\sqrt{35} } } ) = 0.10

          P(Z \leq \frac{x-16.2}{\frac{3.4}{\sqrt{35} } } ) = 0.10

Now, in the z table the critical value of X which represents the below 10% of the probability area is given as -1.282, that means;

                  \frac{x-16.2}{\frac{3.4}{\sqrt{35} } }  =  -1.282

               x - 16.2  =  -1.282 \times {\frac{3.4}{\sqrt{35} } }

                         x  =  16.2 - 0.74 = <u>15.46 minutes</u>

Hence, the mean oil-change time that would there be a 10% chance of being at or below is 15.46 minutes.

8 0
3 years ago
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