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olga nikolaevna [1]
2 years ago
9

I’ve been stuck on this question since beginning of my freshman year! Someone please explain how to do this please??!

Mathematics
1 answer:
dexar [7]2 years ago
8 0

Hi!

There might be different variations into how anyone would approach this problem but this is by far an easy way for me.

In order to solve fractional relationships with a variable, a perfect way to solve them would be to cross multiply and make them equal to each other.

You see the part '3y+12', and when you criss cross over to the other side of the equation, you get three. Multiply that together.

When you see the part '6', when you glide diagonally, you find '4y'. Multiply this together as well. Make them equal to each other.

(<em>This is how you do cross multiplication.)</em>

You should get something like this:

3(3y+12)=6(4y)              Distribute the three on the left side and multiply. Do the same on the right.

9y+36=24y                    Now, you can combine like terms by subtracting 9y to the other side.

36=15y                           Isolate y and divide it by 15.

y=2.4

I was unclear of the answer, so I plugged in 2.4 into the original equation where the y variable was, and got the right answer, so 2.4 should be the correct one no matter how you got it.

I hope this helped!

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Evaluate log 2 base 8​
iren2701 [21]

Answer:  The correct answer is:  " 3 " .

_______________________________

Step-by-step explanation:

_______________________________

The problem given is:

_______________________________

Evaluate:  log 2 base 8 .

_______________________________

Rewrite as:  " log_2}8 = ? _______________  " ;  log_2}8 = ? _______________

_______________________

Take note of the following definition of a logarithm:

_______________________

"   log_{m}n = a " ;  ↔  " m^{a} =n  "  ;

_______________________

in which:  m  refers to the "base" ;

               n  refers to the "argument" ;

               a  refers to the "exponent" ;

______________________________

As such:

       " log_2}8 = ? _______________ "

      ⇔ " 2^{x} = 8 " ; Solve for "x" ;  

 _______________

 Note:  

  2⁰ = 1 ;

  2¹ = 2 ;

  2² = 2 * 2 = 4 ;

  2³ = 2 * 2 * 2 = 8 .

___________________

 → " 2^{x} = 8 " ;

 → " 2^{3} = 8 " ;  since: " 2^{3} = 2  *2 *2 = 8 " ;

 → as such:   " x = 3  " ;

______________________

Thus:

"log 2 base 8 " ;

          = log{_{2}}8 = 3  .

_______________________

Hope this helps!

Best wishes to you!

3 0
3 years ago
I dont understand how to solve
otez555 [7]

Answer:

C

Step-by-step explanation:

The y is decreasing by the same amount, -4

3 0
3 years ago
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I think it may be (6/7)^2
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4 years ago
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Kitty [74]
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3 0
3 years ago
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A flat rectangular piece of aluminum has a perimeter of 62 inches. The length is 15
Salsk061 [2.6K]

Answer:

So, the required width of rectangular piece of aluminium is 8 inches

Step-by-step explanation:

We are given:

Perimeter of rectangular piece of aluminium = 62 inches

Let width of rectangular piece of aluminium = w

and length of rectangular piece of aluminium  = w+15

We need to find width i.e value of x

The formula for finding perimeter of rectangle is: Perimeter=2(Length+Width)\\

Now, Putting values in formula for finding Width w:

Perimeter=2(Length+Width)\\\\62=2(w+15+w)\\62=2(2w+15)\\62=4w+30\\62-30=4w\\4w=32\\w=\frac{32}{4}\\w=8

After solving we get the width of rectangular piece :w = 8

So, the required width of rectangular piece of aluminium is 8 inches

6 0
3 years ago
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