Question

Plz help me with this

Answer 1

Answer:  $\bold{y=sin(4x)+3}$

Step-by-step explanation:

$\text{The standard form of a sine equation is: y=A cos(Bx - C) + D}\\\\\bullet\text{A = amplitude}\\\\\bullet\text{Period = }\dfrac{2\pi}{B}\\\\\bullet\text{Phase Shift = }\dfrac{C}{B}\\\\\bullet\text{D = vertical shift (up if positive, down if negative)}$

The given information is:

• A (amplitude) = 1
• $Period\bigg(\dfrac{2\pi}{B}\bigg)=\dfrac{\pi}{2}}\qquad \implies B=4$
• D (Vertical shift) = +3

$\implies \large\boxed{y=sin(4x)+3}$