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4 years ago

HELP MEEEEEEEEEEEEEEEEEEEEEE −8−(−2+7)2

Mathematics

2 answers:

svetoff [14.1K]4 years ago

4 0

Answer:

- 33

Step-by-step explanation:

Given

- 8 - (- 2 + 7)² ← evaluate the parenthesis

= - 8 - (5)² ← evaluate the exponent

= - 8 - 25

= - 33

Pepsi [2]4 years ago

3 0

Answer:

Step-by-step explanation:

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ANTONII [103]

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3 years ago

Write an equation of the line parallel to y=3x+5 and passing through the point (5,9) in point-slope form. Show all work.

Yuri [45]

Answer:

$y - 9 = 3(x - 5)$

Explanation:

y=3x+5

If you want the equation parallel, then the slope will be: 3

Point Slope Form: $y - y_{1} = m( x - x_{1})$

Since we have everything we need for this equation, we just need to fill in the blanks: $y - 9 = 3(x - 5)$

4 0

2 years ago

Plz help me plz!!!!!!

Mice21 [21]

Answer:

6. was Narbada alienated ...?

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9. Did Sachin behave as if...?

10. did susan look ...?

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13. Were ... and ... aghast to...?

Step-by-step explanation:

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4 0

3 years ago

Select all the points that are on the graph of the line 2x + 4y=20 a.)(0.5) b. (0,10) c. (1,2) d.) (1,4) e.) (5,0) f. (10,0)

zmey [24]

Answer:

(0,5) and (10,0)

Step-by-step explanation:

The equation of the straight line is given by 2x + 4y = 20 .......... (1)

Now, point (0,5) satisfies the equation (1) as putting x = 0, we will get y = 5.

Now, point (0,10) does not satisfy the equation (1) as putiing x = 0, we get y = 5 ≠ 10

Again, point (1,2) does not satisfy the equation (1) as putiing x = 1, we get y = 4.5 ≠ 2

Now, point (1,4) does not satisfy the equation (1) as putiing x = 1, we get y = 4.5 ≠ 4

Again, point (5,0) does not satisfy the equation (1) as putiing y = 0, we get x = 10 ≠ 5

Finally, point (10,0) satisfies the equation (1) as putiing y = 0, we get x = 10 .

Therefore, only points (0,5) and (10,0) are on the graph of the line 2x + 4y = 20 (Answer)

8 0

3 years ago

PLEASE HELP I HAVE AN HOUR LEFT!!

Yuki888 [10]

The statement that correctly describes the horizontal asymptote of g(x) is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

<h3>What are the asymptotes of a function f(x)?</h3>

The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.

The horizontal asymptote is the limit of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, the function is:

$g(x) = \frac{42x^3 - 15}{7x^3 - 4x^2 - 3}$

The horizontal asymptote is given as follows:

$y = \lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} \frac{42x^3 - 15}{7x^3 - 4x^2 - 3} = \lim_{x \rightarrow \infty} \frac{42x^3}{7x^3} = \lim_{x \rightarrow \infty} 6 = 6$

Hence the correct statement is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

More can be learned about asymptotes at brainly.com/question/16948935

#SPJ1

5 0

2 years ago