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Kobotan [32]
3 years ago
8

(04.02 HC) Which statement explains the relationship of sides BA and B'A' after rectangle BADC has been rotated 180° about the o

rigin? coordinate plane with rectangle ABCD at A 3 comma 5, B 1 comma 3, C 5 comma negative 1, and D 7 comma 1 Side B'A' has a slope of −1 and is perpendicular to side BA. Side B'A' has a slope of 1 and is parallel to side BA. Side B'A' has a slope of 1 and is perpendicular to side BA. Side B'A' has a slope of −1 and is parallel to side BA.
Mathematics
2 answers:
yanalaym [24]3 years ago
6 0

Answer:  Side B'A' has a slope of 1 and is parallel to side BA.

saul85 [17]3 years ago
5 0

Answer:

option d) slope of -1 and parallel to side BA

Step-by-step explanation:

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Factor each.<br><br><br> Please help!
Naddika [18.5K]

Answer:

1) The factors of  x^2-3x+2=0 are \mathbf{(x-1)(x-2)=0}

Option C is correct.

3) The factors of  x^2+2x-8=0 are \mathbf{(x-2)(x+4)=0}

Option B is correct.

Step-by-step explanation:

1) Factor : x^2-3x+2=0

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

The middle term : -3x

We can break them as (-2x)( -x)

Solving:

x^2-3x+2=0\\x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0

So, factors of  x^2-3x+2=0 are \mathbf{(x-1)(x-2)=0}

Option C is correct.

3) Factor: x^2+2x-8=0

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

The middle term : 2x

We can break them as (4x)( -2x)

Solving

x^2+2x-8=0\\x^2+4x-2x-8=0\\x(x+4)-2(x+4)=0\\(x-2)(x+4)=0

So, factors of  x^2+2x-8=0 are \mathbf{(x-2)(x+4)=0}

Option B is correct.

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