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2 years ago

13

Un cultivador siembra 4/5 de su granja en frijoles, 3/2 de maíz, ¿En total su granja cuanto cultivo sembrado quedo?

1 answer:

Strike441 [17]2 years ago

4 0

Answer:

can you write this question in English language ????

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Please help me with the problem

Kruka [31]

Oh my gosh...thats a lot. Umm, well let's start with what the equation says. This will break it down to where it's of better understanding. What is the equation asking you to do? You have heard of the acronym "PEMDAS", correct? (Parantheses, Exponents, Multiplication, Division, Addition and Subtraction) Follow that order of operations and see what it is the equation wants done first. Solve it, basically...then we will focus on the actual question parts.

6 0

3 years ago

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Jeremiah and family flew 547 miles on christmas eve last year this year they flew 1,328 miles how many miles did jeremiah fly in

madam [21]

Answer:

1903 miles

Step-by-step explanation:

547+1328=1903

4 0

2 years ago

Read 2 more answers

Plz help me, thank you

Kruka [31]

Answer:

$P=40(1.03526)^{t}$

Step-by-step explanation:

<u>Exponential Growth </u>

The natural growth of some magnitudes can be modeled by the equation:

$P=P_o(1+r)^{t}$

Where P is the actual amount of the magnitude, Po is its initial amount, r is the growth rate and t is the time.

The initial number of bacteria is Po=40 and it doubles (P=2Po) at t=20 min. With that point we can find the value of r:

$2P_o=P_o(1+r)^{20}$

Simplifying:

$(1+r)^{20}=2$

Solving for 1+r:

$1+r=\sqrt[20]{2}$

$1+r=1.03526$

The exponential function that models the situation is:

$\mathbf{P=40(1.03526)^{t}}$

4 0

2 years ago

Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s

Nataliya [291]

Answer:

$f(x)=\frac{1}{2}x^2-4x+5$

Step-by-step explanation:

A parabola is written in the form

$f(x)=a((x-h)^2+k)$ (1)

where:

$h$ is the x-coordinate of the vertex of the parabola

$ak$ is the y-coordinate of the vertex of the parabola

$a$ is a scale factor

For the parabola in the problem, we know that the vertex has coordinates (4,-3), so we have:

$h=4$ (2)

$ak=-3$

From this last equation, we get that $a=\frac{-3}{k}$ (3)

Substituting (2) and (3) into (1) we get the new expression:

$f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3$ (4)

We also know that the parabola contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

$-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6$

So we also get:

$a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}$

So the equation of the parabola is:

$f(x)=\frac{1}{2}((x-4)^2 -6)$ (5)

Now we want to rewrite it in the standard form, i.e. in the form

$f(x)=ax^2+bx+c$

To do that, we simply rewrite (5) expliciting the various terms, we find:

$f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5$

6 0

2 years ago

*Select all that apply.*

Korvikt [17]

I'm for sure know that it is function is linear but i would wait for others to answer also

5 0

3 years ago

Read 2 more answers