The answer could be c or a
Answer:
i. weight of wastage(kg) = 179.775 kg
ii. weight of rice cultivated = 765 kg - 179. 775 kg = 585.225 kg
percentage of rice cultivated = 100 - 23.5 = 76.5%
Step-by-step explanation:
A land of 1000 sq. meter is used to cultivate 765 kg of rice with wastage of 23.5%.
i. The wastage in percentage is 23.5% but the weight of the wastage in weight is 23.5% of 765 kg
weight of wastage = 23.5/100 × 765
weight of wastage = 17977.5/100
weight of wastage(kg) = 179.775 kg
ii. weight and percentage of rice cultivated.
weight of rice cultivated = 765 kg - 179. 775 kg = 585.225 kg
percentage of rice cultivated = 100 - 23.5 = 76.5%
5+(-4)= 1
14+(-13)= 1
So the answer is B. =
I hope this helps
Angles PQT and RQS are vertical angles and angles PQR and TQS are vertical angles.
angle PQS and TQR are straight angles
angles TQP and PQR form a linear pair. they are also adjacent by default. the other angles have these same features.
that should bout do it. hope it helped!
The question is somewhat poorly posed because the equation doesn't involve <em>θ</em> at all. I assume the author meant to use <em>x</em>.
sec(<em>x</em>) = csc(<em>x</em>)
By definition of secant and cosecant,
1/cos(<em>x</em>) = 1/sin(<em>x</em>)
Multiply both sides by sin(<em>x</em>) :
sin(<em>x</em>)/cos(<em>x</em>) = sin(<em>x</em>)/sin(<em>x</em>)
As long as sin(<em>x</em>) ≠ 0, this reduces to
sin(<em>x</em>)/cos(<em>x</em>) = 1
By definition of tangent,
tan(<em>x</em>) = 1
Solve for <em>x</em> :
<em>x</em> = arctan(1) + <em>nπ</em>
<em>x</em> = <em>π</em>/4 + <em>nπ</em>
(where <em>n</em> is any integer)
In the interval 0 ≤ <em>x</em> ≤ 2<em>π</em>, you get 2 solutions when <em>n</em> = 0 and <em>n</em> = 1 of
<em>x</em> = <em>π</em>/4 <u>or</u> <em>x</em> = 5<em>π</em>/4