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Alex777 [14]
3 years ago
7

Which equation demonstrates the additive identity property?

Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
8 0

Answer:

the correct answer is b (7+4i)+0=7+4i

Step-by-step explanation:

Anon25 [30]3 years ago
3 0
(7+4i)+0=7+4i.
Hope it helps
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A new car is purchased for 24600 dollars. The value of the car depreciates at 13.75% per year. What will the value of the car be
liraira [26]

Answer:

The value will be $1,411.20

Step-by-step explanation:

What we do here is to set up an exponential equation to calculate the value.

Mathematically it will look like this;

V = I(1-r)^n

where V is the future value

I is the initial amount = 24,600

r is rate of decrease = 13.75% = 13.75/100 = 0.1375

n is the number of years = 15 years

substituting these values, we have

V = 24,600(1-0.1375)^15

V = 24600(0.8625)^15

V = 1,411.165582454129

= $1,411.20

7 0
3 years ago
Factor -1/2out of -1/2x+6
Volgvan
-\dfrac{1}{2}x+6=-\dfrac{1}{2}\left(\dfrac{-\frac{1}{2}x}{-\frac{1}{2}}+\dfrac{6}{-\frac{1}{2}}\right)=-\dfrac{1}{2}\left(x-\dfrac{6\cdot2}{1}\right)=\boxed{-\dfrac{1}{2}\left(x-12\right)}
3 0
3 years ago
In a school, the ratio of soccer players to volleyball players is 4 : 1.
VLD [36.1K]
4:1 means for every four soccer player there is 1 volleyball player

that means there are four times the number of soccer players than volleyball players
7 0
3 years ago
Evaluate the integral, show all steps please!
Aloiza [94]

Answer:

\displaystyle \int \dfrac{1}{(9-x^2)^{\frac{3}{2}}}\:\:\text{d}x=\dfrac{x}{9\sqrt{9-x^2}} +\text{C}

Step-by-step explanation:

<u>Fundamental Theorem of Calculus</u>

\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given indefinite integral:

\displaystyle \int \dfrac{1}{(9-x^2)^{\frac{3}{2}}}\:\:\text{d}x

Rewrite 9 as 3²  and rewrite the 3/2 exponent as square root to the power of 3:

\implies \displaystyle \int \dfrac{1}{\left(\sqrt{3^2-x^2}\right)^3}\:\:\text{d}x

<u>Integration by substitution</u>

<u />

<u />\boxed{\textsf{For }\sqrt{a^2-x^2} \textsf{ use the substitution }x=a \sin \theta}

\textsf{Let }x=3 \sin \theta

\begin{aligned}\implies \sqrt{3^2-x^2} & =\sqrt{3^2-(3 \sin \theta)^2}\\ & = \sqrt{9-9 \sin^2 \theta}\\ & = \sqrt{9(1-\sin^2 \theta)}\\ & = \sqrt{9 \cos^2 \theta}\\ & = 3 \cos \theta\end{aligned}

Find the derivative of x and rewrite it so that dx is on its own:

\implies \dfrac{\text{d}x}{\text{d}\theta}=3 \cos \theta

\implies \text{d}x=3 \cos \theta\:\:\text{d}\theta

<u>Substitute</u> everything into the original integral:

\begin{aligned}\displaystyle \int \dfrac{1}{(9-x^2)^{\frac{3}{2}}}\:\:\text{d}x & = \int \dfrac{1}{\left(\sqrt{3^2-x^2}\right)^3}\:\:\text{d}x\\\\& = \int \dfrac{1}{\left(3 \cos \theta\right)^3}\:\:3 \cos \theta\:\:\text{d}\theta \\\\ & = \int \dfrac{1}{\left(3 \cos \theta\right)^2}\:\:\text{d}\theta \\\\ & =  \int \dfrac{1}{9 \cos^2 \theta} \:\: \text{d}\theta\end{aligned}

Take out the constant:

\implies \displaystyle \dfrac{1}{9} \int \dfrac{1}{\cos^2 \theta}\:\:\text{d}\theta

\textsf{Use the trigonometric identity}: \quad\sec^2 \theta=\dfrac{1}{\cos^2 \theta}

\implies \displaystyle \dfrac{1}{9} \int \sec^2 \theta\:\:\text{d}\theta

\boxed{\begin{minipage}{5 cm}\underline{Integrating $\sec^2 kx$}\\\\$\displaystyle \int \sec^2 kx\:\text{d}x=\dfrac{1}{k} \tan kx\:\:(+\text{C})$\end{minipage}}

\implies \displaystyle \dfrac{1}{9} \int \sec^2 \theta\:\:\text{d}\theta = \dfrac{1}{9} \tan \theta+\text{C}

\textsf{Use the trigonometric identity}: \quad \tan \theta=\dfrac{\sin \theta}{\cos \theta}

\implies \dfrac{\sin \theta}{9 \cos \theta} +\text{C}

\textsf{Substitute back in } \sin \theta=\dfrac{x}{3}:

\implies \dfrac{x}{9(3 \cos \theta)} +\text{C}

\textsf{Substitute back in }3 \cos \theta=\sqrt{9-x^2}:

\implies \dfrac{x}{9\sqrt{9-x^2}} +\text{C}

Learn more about integration by substitution here:

brainly.com/question/28156101

brainly.com/question/28155016

4 0
2 years ago
What is 150% of 5000? Round to the nearest hundredth (if necessary).
sveticcg [70]
The answer is 7,500 because 150% is the same as 1.5 x 5000.
5 0
3 years ago
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