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Zigmanuir [339]
3 years ago
7

In circle D, which is a secant? Geometry pls answer!!!

Mathematics
2 answers:
Inessa [10]3 years ago
4 0
I believe line G_H is a secant.
4vir4ik [10]3 years ago
4 0

Answer:

GH

Step-by-step explanation:

You might be interested in
Using interval notation , identify the domain for the function!!! Math 3 - 10 points. Help needed
In-s [12.5K]

Answer:

The domain by the interval notation is (-∞ , 3)∪(3 , 4)∪(4 , ∞) ⇒ 3rd answer

Step-by-step explanation:

* Lets revise how to find the domain of the function

- The domain is all values of  x  that make the expression defined

- To find where the expression is undefined put the denominator

  equal 0, to get the values of x which make denominator equal to 0

- The domain will be all the real number except those values

* Now lets solve the problem

∵ f(x) = (x² - 9)/(x² - 7x + 12)

- Let the denominator x² − 7x + 12  equal to  0

∵ x² − 7x + 12 = 0 ⇒ factorize it

- Consider the form  x² + bx + c

- Find a pair of integers whose product is c and whose sum is b

- In this case, whose product is 12 and whose sum is −7

- They are -3 and -4

- Write the factored form using these integers.

∴ (x -3)(x - 4) = 0 ⇒ put each bracket = 0

∴ x - 3 = 0 or x - 4 = 0

∵ x - 3 = 0 ⇒ add 3 to both sides

∴ x = 3

∵ x - 4 = 0 ⇒ add 4 to both sides

∴ x = 4

∴ The domain of f(x) is all real number except 3 and 4

* The domain by the interval notation is

 (-∞ , 3)∪(3 , 4)∪(4 , ∞)

7 0
3 years ago
Which of the following is equivalent to 5−1?
Troyanec [42]

Answer:

what r the options

Step-by-step explanation:

5 0
3 years ago
What is the image of point (4, 5) after a counterclockwise rotation of 270º about the origin?
tia_tia [17]
The answer is (5, -4).
4 0
3 years ago
CAN SOMEONE HELP JUST WANNA CHECK IF IM RIGHT
monitta

Answer:

you are right

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
I will give brainelest but i need help on the graph
const2013 [10]

Answer:

1)   (6,2) (9,2) (3,8) (3,5)

2)   (2,-5) (5,-5) (-1,-11) (-1,-8)

Step-by-step explanation:

For the first question, your reflecting over the x-axis into quadrant I, so you just need to make all the coordinates positive.  The numbers stay the same - you just get rid of the negative signs.  (6,2) (9,2) (3,8) (3,5)

For the second problem, you subtract 4 from the x-value, and 3 from the y-value.

(6,-2) becomes (2,-5)

(9,-2) becomes (5,-5)

(3,-8) becomes (-1,-11)

(3,-5)  becomes (-1,-8)

3 0
4 years ago
Read 2 more answers
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