The answer could be 2b+3/b-2=3b/+2
No there will not be enough. Think about it this way. If each slice is 1/4 of the pizza, then each pizza can only feed 4 people. If you have 3 of these pizzas, then you can feed 12 people at most. Since there are 14 kids, you won't have enough.
Answer: For part A, the formula for the employee's pay is <em><u>P</u></em>ay = hourly <em><u>r</u></em>ate times <em><u>h</u></em>ours . P = r × h The equation is P = 13h To find how many hours are required to earn a given amount, fill in given values and solve for the missing variable . 7800 = 13h h= 7800/13 600 hours needed.
For part B, the formula for this employee's pay is <em><u>P</u></em>ay = <u><em>B</em></u>onus + hourly <em><u>r</u></em>ate times <em><u>h</u></em>ours . P = b + rh
330 = 90 + r(24) 330 - 90 = 24r . 240 = 24r 240/24 = r . r = 10
The employee's pay rate is $10 per hour.
the distance form X to Y is clearly -6 to 0 is 6 units, and 0 to 8 is 8 units, so 6 + 8 = 14 units.
now, for XZ and ZY we can simply use as stated, the distance formula to get those and then add them all to get the perimeter.
![\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ X(\stackrel{x_1}{-6}~,~\stackrel{y_1}{2})\qquad Z(\stackrel{x_2}{5}~,~\stackrel{y_2}{8})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ XZ=\sqrt{[5-(-6)]^2+[8-2]^2}\implies XZ=\sqrt{(5+6)^2+(8-2)^2} \\\\\\ XZ=\sqrt{121+36}\implies \boxed{XZ=\sqrt{157}} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%20%5C%5C%5C%5C%20X%28%5Cstackrel%7Bx_1%7D%7B-6%7D~%2C~%5Cstackrel%7By_1%7D%7B2%7D%29%5Cqquad%20Z%28%5Cstackrel%7Bx_2%7D%7B5%7D~%2C~%5Cstackrel%7By_2%7D%7B8%7D%29%5Cqquad%20%5Cqquad%20d%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20XZ%3D%5Csqrt%7B%5B5-%28-6%29%5D%5E2%2B%5B8-2%5D%5E2%7D%5Cimplies%20XZ%3D%5Csqrt%7B%285%2B6%29%5E2%2B%288-2%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20XZ%3D%5Csqrt%7B121%2B36%7D%5Cimplies%20%5Cboxed%7BXZ%3D%5Csqrt%7B157%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ Z(\stackrel{x_2}{5}~,~\stackrel{y_2}{8})\qquad Y(\stackrel{x_2}{8}~,~\stackrel{y_2}{2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ ZY=\sqrt{(8-5)^2+(2-8)^2}\implies ZY=\sqrt{9+36}\implies \boxed{ZY=\sqrt{45}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{perimeter}{14+\sqrt{157}+\sqrt{45}}\qquad \approx \qquad 33.2](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%20%5C%5C%5C%5C%20Z%28%5Cstackrel%7Bx_2%7D%7B5%7D~%2C~%5Cstackrel%7By_2%7D%7B8%7D%29%5Cqquad%20Y%28%5Cstackrel%7Bx_2%7D%7B8%7D~%2C~%5Cstackrel%7By_2%7D%7B2%7D%29%5Cqquad%20%5Cqquad%20d%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20ZY%3D%5Csqrt%7B%288-5%29%5E2%2B%282-8%29%5E2%7D%5Cimplies%20ZY%3D%5Csqrt%7B9%2B36%7D%5Cimplies%20%5Cboxed%7BZY%3D%5Csqrt%7B45%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7Bperimeter%7D%7B14%2B%5Csqrt%7B157%7D%2B%5Csqrt%7B45%7D%7D%5Cqquad%20%5Capprox%20%5Cqquad%2033.2)
Check the picture below.
make sure your calculator is in Degree mode.
