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Natali5045456 [20]
1 year ago
6

Write an equation for each line. m=-5 and the y -intercept is (0,-7) .

Mathematics
1 answer:
Veronika [31]1 year ago
6 0

The equation of the line for given values is y = -5x - 7.

<h3>Given a point and a slope, how do you build an equation for a line?</h3>

When you know the slope of the line to be investigated and the provided point is also the y intercept, you may utilize the slope intercept formula, y = mx + b. (0, b). The y value of the y intercept point is denoted by the symbol b in the formula.

The standard equation of straight line is y = mx + c.

Given m = -5 and y - intercept is -7

So, the equation of the line becomes y = -5x - 7

To learn more about equation of the line from given link

brainly.com/question/18831322

#SPJ4

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60 is 10 times greater than 6

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The combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 m
rewona [7]

Answer:

Approximately 50 pounds less carbon (in CO₂) will be produced by the second auto on this trip.

Step-by-step explanation:

We have been given that the combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 miles.

Let us find amount of fuel used by autos by dividing the total distance by their mileage.

\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\frac{\text{ 20 miles}}{\text{gallon}}}

\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\text{ 20 miles}}\times \text{gallon}

\text{Fuel used by 1st auto}=30 \text{ gallons}

\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\frac{\text{ 30 miles}}{\text{gallon}}}

\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\text{ 30 miles}}\times \text{gallon}

\text{Fuel used by 2nd auto}=20 \text{ gallons}

Let us find the difference of fuel used by both autos.

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\text{Number of gallons that 2nd auto used less than 1st auto}=10

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Since 2nd auto used 10 gallons less than 1st auto, therefore, 2nd auto will produce 50 pounds less carbon than 1st auto.

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