3 years ago

4

Mathematics

1 answer:

Ulleksa [173]3 years ago

8 0

Answer:

13) 0.61 cent

14) 13.78 $

15) 3.82 $

Step-by-step explanation:

Hope this helps

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No is divisible by 7 if n is divided by 2 3 4 5 the remainder is 1 what is the smallest value that n could b

kvv77 [185]

Answer: $301$

Step-by-step explanation:

Since, The LCM of numbers given numbers $2$ , $3$ , $4$ and $5$ is $60$ .

Thus, the number that gives 1 as reminder and is the multiple of 7 is $60 n + 1$

Where n is any positive integer,

Since, For $n = 5$ ,

The number is, $60\times 5 + 1 = 300 + 1 = 301$

Which is divisible by $7$ .

Thus, the required number is 301.

Note : For n = 1, 2 3 and 4, numbers are 61, 121, 181 and 241

But they are not the multiple of 7.

7 0

3 years ago

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3/4 divided by N = 6/5<br> What are the remaining fact family number sentences?

Mice21 [21]

Answer:

5/8 or 0.625

Step-by-step explanation:

If you have a question somewhat like this use math way

7 0

2 years ago

The balance in two separate bank accounts grows each month at different rates. The growth rates for both accounts are represente

Leno4ka [110]

That would be 42(x) greater than 809(x)

8 0

3 years ago

What is equivalent to 2x^2+9x+9

melamori03 [73]

(2x + 3) • (x + 3)

2x • x = 2x^2

2x • 3 = 6x

3 • x = 3x

3 • 3 = 9

6x and 3x combine to get 9x, which when all written out is equal to your original trinomial.

7 0

3 years ago

The amount of carbon-14 present in a paint after t years is given by y equals y Subscript o Baseline e Superscript negative 0.0

Anni [7]

Answer:

16,383.33 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of carbon-14 after t years,

$y = y_0 e^{-0.00012t}$

Where,

$y_0$ = initial amount,

∵ 14% of $y_0$ = $\frac{14}{100}y_0$ = $\frac{7}{50}y_0$

$\frac{7}{50}y_0= y_0 e^{-0.00012t}$

$\frac{7}{50}=e^{-0.00012t}$

Taking ln both sides,

$\ln(\frac{7}{50})=-0.00012t$

$-1.966=-0.00012t$

$\implies t =\frac{-1.966}{-0.00012}=16383.33$

Hence, the painting would be 16383.33 years old ( approx )

5 0

3 years ago