<span><span><span>6<span>x2</span></span>+<span>11x</span></span>−35</span><span>=<span><span>(<span><span>3x</span>−5</span>)</span><span>(<span><span>2x</span>+7</span><span>)</span></span></span></span>
Thank you for posting your question here. I hope the answer below will help.
Vo=110 feet per second
<span>ho=2 feet </span>
<span>So, h(t) = -16t^2 +110t +2 </span>
<span>Take the derivative: h'(t) = 110 -32t </span>
<span>The maximum height will be at the inflection when the derivative crosses the x-axis aka when h'(t)=0. </span>
<span>So, set h'(t)=0 and solve for t: </span>
<span>0 = 110 -32t </span>
<span>-110 = -32t </span>
<span>t=3.4375 </span>
<span>t=3.44 seconds </span>
Area equals 86.7 cm squared
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