Answer:
Answer is at the bottom!!
Step-by-step explanation:
y = - \frac{2}{5} x - 2
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y-intercept )
rearrange 2x + 5y = 10 into this form
subtract 2x from both sides
5y = - 2x + 10 ( divide all terms by 5 )
y = - \frac{2}{5} x + 2 ← point- slope form with slope m = - \frac{2}{5}
Parallel lines have equal slopes hence
y = - \frac{2}{5} x + c is the partial equation of the parallel line
to find c, substitute ( 5, - 4 ) into the partial equation
- 4 = - 2 + c ⇒ c = - 4 + 2 = - 2
y = - \frac{2}{5} x - 2 ← equation of parallel line
Hope this helps!!
Answer:
Transitive Property of Congruency;If parallel lines have a transversal, then alternate interior angles are congruent.
The Transitive Property of Congruency:
If 2 angles are congruent to a third angle, then they are congruent to each other. So, since angles 4 and 5 are both congruent to angle 1, they are congruent to each other.
Angles 4 and 5 are alternate interior angles. Therefore, if parallel lines have a transversal, alternate interior angles are congruent.
A function on a graph to figure it out you can do the line test where you draw a line through the graph and if the line touches two points its not a function. With this in mind bottom right is for sure one and the top left looks like one but i cant really tell...
Step-by-step explanation:
Answer:
A) Dimensions;
Length = 20 m and width = 10 m
B) A_max = 200 m²
Step-by-step explanation:
Let x and y represent width and length respectively.
He has 40 metres to use and he wants to enclose 3 sides.
Thus;
2x + y = 40 - - - - (eq 1)
Area of a rectangle = length x width
Thus;
A = xy - - - (eq 2)
From equation 1;
Y = 40 - 2x
Plugging this for y in eq 2;
A = x(40 - 2x)
A = 40x - 2x²
The parabola opens downwards and so the x-value of the maximum point is;
x = -b/2a
Thus;
x = -40/2(-2)
x = 10 m
Put 10 for x in eq 1 to get;
2(10) + y = 40
20 + y = 40
y = 40 - 20
y = 20m
Thus, maximum area is;
A_max = 10 × 20
A_max = 200 m²
The arc subtends an angle of 300° .
Step-by-step explanation:
Radius = 75 cm
Arc length = 125π cm
Arc length = (θ/360) (2πr)
125π = (θ/360) (2π x 75)
125π = (θ/360) (150π)
125π/150π = (θ/360)
5/6 = (θ/360)
(5/6) (360) = θ
θ = 300°
The arc subtends an angle of 300° .
